Options A, C, and D qualify since each contains at least half a pint of paint.
2.07. The mean for X is calculated as 1.00, and for Y as 1.07, leading to the total of X + Y = 1 + 1.07 = 2.07.
Response:
a. 55 cars
b. 25 cars
Detailed explanation:
Let’s denote the quantity of cars with stereo systems as N(ss), those with air conditioning as N(ac), and those with sunroofs as N(sr).
We find that:
N(ss) = 30
N(ac) = 30
N(sr) = 40
N(ss and ac and sr) = 15
N(at least two) = 30
a.
To calculate how many cars possess at least one feature (N(at least one) or N(ss or ac or sr)), we apply:
N(ss or ac or sr) = N(ss) + N(ac) + N(sr) - N(ss and ac) - N(ss and sr) - N(ac and sr) + N(ss and ac and sr)
N(ss or ac or sr) = 30 + 30 + 40 - (N(at least two) + 2*N(ss and ac and sr)) + 15
Substituting, we find N(ss or ac or sr) = 30 + 30 + 40 - (30 + 2*15) + 15 = 55
b.
For those cars that have exactly one feature, we have:
N(only one) = N(at least one) - N(at least two)
N(only one) = 55 - 30 = 25
The smallest number of trips he must make is 5. Since he can carry only 3 bottles per trip, 5 trips would allow him to transport 15 bottles.
Though it might seem like 4 trips could suffice, as 4 times 3 is 12, that's one bottle short of 13.
Hence, an additional trip is needed to carry the last bottle, totaling 5 trips.
