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aalyn
29 days ago
12

The in situ moist unit weight of a soil is 17.3 kN/m3 and the moisture content is 16%. The specific gravity of soil solids is 2.

72. This soil is to be excavated and transported to a construction site for use in a compacted fill. If the specification calls for the soil to be compacted to a minimum dry unit weight of 18.1 kN/m3 at the same moisture content of 16%, how many cubic meters of soil from the excavation site are needed to produce 2000 m3 of compacted fill?
Engineering
1 answer:
Mrrafil [253]29 days ago
3 0

Answer:

Explanation:

Given that,

Moisture content w = 16%

The in situ moist unit weight of soil: γ(in situ) = 17.3 kN/m³

Specific gravity of the soil

G(s) = 2.72

Minimum dry unit weight of the soil

γd(compacted) = 18.1 kN/m³

Moisture content remains the same

w = 16%

Question:

How much cubic meters of soil are necessary from the excavation site to create 2000 m³ of compacted fill?

Now, let's work out the in situ dry unit weight γd(in-situ) with the formula:

γd(in-situ) = γ(in-situ) / [1 + (w/100)]

γd(in-situ) = 17.3 / [1 + (16/100)]

γd(in-situ) = 17.3 / (1 + 0.16)

γd(in-situ) = 17.3 / 1.16

γd(in-situ) = 14.89 kN/m³

To find out the Volume of soil to be excavated (Vex):

Let the Volume to be excavated = V

We will use the relationship:

V = V(fill) × γd(compacted) / γd(in situ)

Given that, V(fill) = 2000 m³

V(fill) is the compacted fill volume.

Therefore, we have:

V = V(fill) × γd(compacted) / γd(in situ)

Vex = 2000 × 18.1 / 14.89

Vex = 2423.34 m³

Thus, the soil volume to be excavated equals 2423.34 m³.

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Here is the JAVA program:

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int[] origList = new int[NUM_VALS];

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Explanation:

If you wish to print the product of origList alongside offsetAmount values vertically, this can be done in this manner:

import java.util.Scanner;

public class VectorElementOperations {

public static void main(String[] args) {

final int NUM_VALS = 4;

int[] origList = new int[NUM_VALS];

int[] offsetAmount = new int[NUM_VALS];

int i;

origList[0] = 20;

origList[1] = 30;

origList[2] = 40;

origList[3] = 50;

offsetAmount[0] = 4;

offsetAmount[1] = 6;

offsetAmount[2] = 2;

offsetAmount[3] = 8;

for(i = 0; i <= origList.length - 1; i++){

origList[i] *= offsetAmount[i];

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80

180

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The program is shown with the output as a screenshot along with the example's input.

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