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const2013
2 months ago
6

A piece of corroded metal alloy plate was found in a submerged ocean vessel. It was estimated that the original area of the plat

e was 800 cm2 and that approximately 7.6 kg had corroded away during the submersion. Assuming a corrosion penetration rate of 4 mm/yr for this alloy in seawater, estimate the time of submersion in years. The density of the alloy is 4.5 g/cm3.
Engineering
1 answer:
Mrrafil [318]2 months ago
8 0

Answer:

t = 5.27 years

Explanation:

Firstly, the corrosion penetration rate is defined by the formula;

CPR = (KW)/(ρAt)

Where;

K = constant based on exposed area A.

W - mass lost over time

t- duration

ρ - density

A - area exposed

From the problem, we have;

W = 7.6kg or 7.6 x 10^(6) mg

CPR = 4 mm/yr

ρ = 4.5 g/cm³

Area = 800 cm²

K is a constant valued at 87.6cm

Rearranging the CPR formula to isolate t, we derive;

t = KW/(ρA(CPR))

t = (87.6 x 7.6 x 10^(6))/(4.5 x 800 x 4) = 46233.3 hours

The duration in question needs to be expressed in years.

Thus, converting hours to years;

There are 8760 hours in a year.

Therefore;

t = 46233.3/8760 = 5.27 years.

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Answer:

a) F = 736.065\,lbf, b) \mu_{k} = 0.15

Explanation:

a) The uniform dresser can be modeled using specific equilibrium equations:

\Sigma F_{x} = F - \mu_{k}\cdot N = 0

\Sigma F_{y} = N-m\cdot g=0

Following some algebraic manipulations, the formulated equation is derived:

F = \mu_{k}\cdot m \cdot g

F = (0.25)\cdot (90\,lbm)\cdot (32.714\,\frac{ft}{s^{2}} )

F = 22.5\,lbf

b) Similarly, the man can be represented by a set of equilibrium equations:

\Sigma F_{x} = -F + \mu_{k}\cdot N = 0

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After some algebraic changes, the expression for the coefficient of static friction comes out as:

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\mu_{k} = \frac{22.5\,lbf}{150\,lbf}

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2 months ago
A 227 pound compressor is supported by four legs that contact the floor of a machine shop. At the bottom of each leg there is a
choli [298]

Answer:

1.312 in

Explanation:

The details provided in the question are:

The weight of the compressor, W is 227 pounds.

It has 4 legs.

The maximum permissible pressure is 42 psi.

Let F represent the force exerted by each leg.

Thus,

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or

227 pounds = 4F,

implying that:

F = 56.75 pounds.

Furthermore,

Force = Pressure × Area,

therefore:

56.75 pounds = 42 psi × πr²  [ r signifies the radius of one leg]

Consequently, we find:

r² = 0.4301,

and thus:

r = 0.656;

resulting in a diameter equal to 2r = 2 × 0.656,

which equals 1.312 in.

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Explanation: see attachment below

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