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1 month ago

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Engineering

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grin007 [323]1 month ago

7 0

Answer:

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A 90-hp (shaft output) electric car is powered by an electric motor mounted in the engine compartment. If the motor has an avera

pantera1 [306]

Answer:

Heat supply rate is measured at 8.901 horsepower.

Explanation:

Energy efficiency of the electric vehicle, as per Thermodynamics ( $\eta$ ), is the proportion of translational mechanical power ( $\dot E_{out}$ ), expressed in horsepower, and electrical energy ( $\dot E_{in}$ ), also in horsepower. The heat supply rate ( $\dot E_{l}$ ), indicated in horsepower, that the motor delivers to the engine bay under full load can be determined by subtracting the translational mechanical energy from the electric energy. This is expressed as:

$\eta = \frac{\dot E_{out}}{\dot E_{in}}$ (1)

$\dot E_{l} = \dot E_{in}-\dot E_{out}$ (2)

$\dot E_{l} = \left(\frac{1}{\eta}-1\right)\cdot \dot E_{out}$ (3)

If we have the values of $\eta = 0.91$ and $\dot E_{out} = 90\,hp$ , the heat supply rate can be calculated as:

$\dot E_{l} = \left(\frac{1}{0.91}-1 \right)\cdot (90\,hp)$

$\dot E_{l} = 8.901\,hp$

The heat supply rate amounts to 8.901 horsepower.

4 0

3 months ago

6.15. In an attempt to conserve water and to be awarded LEED (Leadership in Energy and Environmental Design) certification, a 20

Viktor [391]

Explanation:

At a temperature of $33^{\circ} C$ and relative humidity of 86%, the humidity ratio stands at 0.0223 with a specific volume of 14.289.

At a temperature of $33^{\circ} C$ and relative humidity of 40%, the humidity ratio is 0.0066 while the specific volume is 13.535.

To determine the mass of air, the following formula can be used:

$\begin{aligned}m _{1} &=\frac{ v }{ v }(1- w ) \\&=\frac{1 \times 10^{5}}{13.535}(1-0.0066) \\&=7339.49 lb / min \\v _{ a } &=\frac{ m _{1} v }{(1- w )} \\v _{ a } &=\frac{7339.49 \times 14.289}{(1-0.0223)} \\v _{ a } &=107266.0 ft ^{3} / min\end{aligned}$

Now, we will calculate the volume

$\begin{aligned}m _{ w } &=\frac{ v _{ a }}{ v _{ a }} w _{ a }-\frac{ v _{ i }}{ v _{ i }} w _{ i } \\&=\frac{107266.0}{14.289} \times 0.0223-\frac{100000}{13.535} \times 0.0066 \\&=118.64 lb / min\end{aligned}$

The duration required to fill the cistern can be determined with the equation:

$Time $=\frac{\text { cistern volume }}{\text { removal water perminute volume }}$$

By substituting the values into the preceding formula, we find:

$$\frac{\left(15 \times 10^{3} L\right) \times\left(0.0353147 ft ^{3} / L \right)}{(118.641 b / min ) \times\left(\frac{1}{62.41 lb / ft ^{3}}\right)}$\\$=279.09$ minutes\\$=4.65$ hours.$

Thus, the hours necessary to fill the cistern amount to 4.65 hours.

3 0

2 months ago

An art collector is bidding on a statue that would complete a collection he is trying to assemble. The statue is being sold in a

Kisachek [356]

Answer: Equal to the collector’s maximum willingness to pay for the statue.

Explanation:

The Vickrey auction, often referred to as a sealed second-price auction, is a bidding format named after the Canadian economist Vickrey. In this auction style, participants submit bids in a concealed manner, preventing others from viewing the amounts being offered.

The collector should bid an amount he or she is comfortable paying for the statue, to ensure they do not feel disadvantaged by the bidding process. In this auction system, the final price paid corresponds to the second-highest bid rather than the highest bid submitted.

8 0

3 months ago

The force of magnitude F acts along the edge of the triangular plate. Determine the moment of F about point O. Find the general

Daniel [329]

Answer:

M_o = 18.84 N*m clockwise.

Explanation:

Given:

- Force F = 120 N

- Length b = 610 mm

- Height h = 330 mm

Required:

Calculate the moment M_o at the origin and its direction:

Solution:

- The force is divided into components F_x and F_y along the base b and height h, respectively:

F_x = F*cos(Q)

F_x = F*(h / sqrt(h² + b²))

F_x = 120*(330 / sqrt(330² + 610²))

F_x = 57.098 N

- The F_y component can be excluded as it passes through the origin, resulting in zero moment.

- The moment at point O is calculated as:

M_o = F_x * h

M_o = 57.098*.33

M_o = 18.84 N*m clockwise.

3 0

2 months ago