Answer:
81°C.
Justification:
We can arrive at this conclusion using the formula:
Q = m.c.ΔT,
where Q denotes the heat lost by water (Q = - 1200 J).
m represents the mass of water (m = 20.0 g).
c indicates the specific heat of water (c = 4.186 J/g.°C).
ΔT signifies the difference between the starting temperature and the final temperature (ΔT = final T - initial T = final T - 95.0°C).
Given Q = m.c.ΔT
It follows that (- 1200 J) = (20.0 g)(4.186 J/g.°C)(final T - 95.0°C ).
(- 1200 J) = 83.72 final T - 7953.
∴ final T = (- 1200 J + 7953)/83.72 = 80.67°C ≅ 81.0°C.
Consequently, the correct answer is: 81°C.
The formula for Molarity is given by:
M = moles / V
To isolate V,
V = moles / M ------------------(1)
Moles can also be calculated as:
moles = mass / M.mass -------------(2)
Substituting the value of moles from equation 2 into equation 1 yields:
V = (mass / M.mass) / M
Plugging in the numbers gives:
V = (45 g / 164 g/mol) / 1.3 mol/dm³
V = 0.21 dm³.
It's important to remember that 1 pint equals 473.1765 mL, therefore 11 pints amounts to 5204.9415 mL.
We can formulate a proportion based on the problem statement
(85 mg glucose/ 100 mL) times (1 g/ 1000 mg) = 4.4242 grams of glucose
