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wolverine
2 months ago
9

Translate to an algebraic expression n−1 increased by 110%

Mathematics
1 answer:
tester [12.3K]2 months ago
6 0

Answer:

Part 1) The algebraic expression can be represented as 1.10(n-1)  or 1.10n-1.10

Part 2) The algebraic expression is represented as \frac{1.10}{n}

Step-by-step explanation:

Part 1) The expression (n-1) raised by 110%

Recognizing that

110%=110/100=1.10

thus,

The algebraic representation of (n-1) increased by 110% translates to 1.10 multiplied by (n-1).

1.10(n-1)

Expanded

1.10n-1.10

Part 2) The expression n^(-1) raised by 110%

<pGiven that

110%=110/100=1.10

therefore, the representation of n^(-1) increased by 110% becomes 1.10 multiplied by n^(-1).

Remember that

n^{-1}=\frac{1}{n}

thus,

1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}

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7 0
2 months ago
Could you help me to solve the problem below the cost for producing x items is 50x+300 and the revenue for selling x items is 90
tester [12383]

Answer:

Función de beneficios: P(x) = -0.5x^2 + 40x - 300

beneficio de $50: x = 10 y x = 70

NO es posible generar un ingreso de $2,500, ya que el máximo beneficio es de $500

Step-by-step explanation:

(Suponiendo que la función de ingresos es 90x−0.5x^2)

La función de costo está dada por:

C(x) = 50x + 300

Y la función de ingresos se expresa como:

R(x) = 90x - 0.5x^2

La función de beneficios se determina restando los costos de los ingresos, por lo que tenemos:

P(x) = R(x) - C(x)

P(x) = 90x - 0.5x^2 - 50x - 300

P(x) = -0.5x^2 + 40x - 300

Para encontrar los puntos donde los beneficios son $50, usamos P(x) = 50 y luego hallamos los valores de x:

50 = -0.5x^2 + 40x - 300

-0.5x^2 + 40x - 350 = 0

x^2 - 80x + 700 = 0

Aplicando la fórmula de Bhaskara, obtenemos:

\Delta = b^2 - 4ac = (-80)^2 - 4*700 = 3600

x_1 = (-b + \sqrt{\Delta})/2a = (80 + 60)/2 = 70

x_2 = (-b - \sqrt{\Delta})/2a = (80 - 60)/2 = 10

Los valores de x que resultan en un beneficio de $50 son x = 10 y x = 70

Para verificar si es posible obtener un beneficio de $2,500, necesitamos considerar el beneficio máximo, que es el máximo de la función P(x).

El valor máximo de P(x) se encuentra en el vértice. La coordenada x del vértice se calcula como:

x_v = -b/2a = 80/2 = 40

Con este valor de x, podemos calcular el beneficio máximo:

P(40) = -0.5(40)^2 + 40*40 - 300 = $500

El beneficio máximo es de $500, así que NO es posible generar un beneficio de $2,500.

5 0
21 day ago
PATS, PETE AND KOFFI ANNUAL SALARIES AGGREGATE TO 200,000.00 A YEAR PETE MAKES $11000.00 MORE THAN KOFFI AND PAT MAKES $1000.00
zzz [12365]

Respuesta:

El salario mensual de Koffi: $3500 ($42000 anuales)

Salario mensual de Pete: $4416.7 ($53000 anuales)

Salario mensual de Pat: $8750 ($105000 anuales)

Explicación paso a paso:

Sea x el salario anual de Pat

Sea y el salario anual de Pete

Sea z el salario anual de Koffi

Según el enunciado, sus salarios anuales suman $200000 es decir, x + y + z= $200000

Pete gana $11000 más que Koffi anualmente, lo que significa que y = $11000 + z

Pat gana $1000 menos que el doble (×2) del salario anual de Pete, es decir, x = 2y - $1000

Así, tenemos 3 ecuaciones:

(1)..... x + y + z= $200000

(2).... y = $11000 + z

(3).... x = 2y - $1000

Primero, sustituimos y en la ecuación (3), es decir,

x = 2(11000 + z) - 1000

x = 22000 + 2z - 1000

x = 21000 + 2z............ (4)

Luego incorporamos las ecuaciones (4) y (2) en la ecuación (1) para encontrar z:

x + y + z = 200000

21000 + 2z + 11000 + z + z = 200000

4z + 32000 = 200000

4z = 200000 - 32000

4z = 168000

z = 42000

Así que z (salario anual de Koffi) es de $42000.

Para conocer y, sustituimos z en la ecuación (2).

y = 11000 + z

y = 11000 + 42000

y = 53000

Por lo tanto, y (salario anual de Pete) es de $53000

Para hallar x, sumamos $42000 y $53000, y restamos de $200000 es decir, 42000 + 53000 = 95000

200000 - 95000 = 105000

Por lo tanto, x (salario anual de Pat) es de $105000.

Para obtener el salario mensual de cada individuo, dividimos su salario anual entre 12:

Koffi (z) = 42000/12 = $3500

Pete (y) = 53000/12 = $4416.7

Pat (x) = 105000/12 = $8750

4 0
1 month ago
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