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Natali5045456
7 days ago
13

Trains A and B, 200 km apart on the same straight track, travel at speeds of 50 km/hr and 65 km/hr respectively. At the end of 1

hour, the distance between the trains could not
Mathematics
1 answer:
Leona [4.2K]7 days ago
4 0

Answer:

Ok, la distancia inicial entre los trenes es de 200 km:

IPa(0s) - P(0s)I = 200 km.

donde Pa representa la ubicación del tren A y Pb representa la ubicación del tren B.

La velocidad del tren A es:

Sa = 50 km/h

Sb = 65 km/h

Recuerda la relación:

Distancia = Velocidad * tiempo.

<pAsí, en una hora, la distancia recorrida por el tren A es:

Distancia = 50 km/h * 1 h = 50 km

<pLa distancia recorrida por el tren B es:

distancia = 65 km/h * 1 h = 65 km.

<pSi al inicio el tren A está 200 km adelante del tren B, entonces tenemos:

Pa - Pb = (Pa(0s) + 50 km) - (Pb(0s) + 65 km)

= (Pa(0s) - Pb(0s)) + (50 km - 65 km) = 200 km - 15 km = 185 km.

<pAhora, si el tren B estaba 200 km por delante del tren A, tenemos:

Pb - Pa = (Pb(0s) + 65 km) - (Pa(0s) - 50 km) =

(Pb(0s) - Pa(0s)) + (65 km - 50 km) = 200 km + 15 km = 215 km

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Find the coefficient of x2 in (3x2 – 5) (4 + 4x2), expand using algebraic expressions and answer
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- 8

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Stackable polystyrene cups have a height h1=12.5 cm. Two stacked cups have a height of h2=14 cm. Three stacked cups have a heigh
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Approximately 59 stacked cups.

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Height of one cup = 12.5 cm,

Height of two cups stacked = 14 cm,

Height of three cups stacked = 15.5 cm,

...and so on.

This situation can be described by an arithmetic sequence,

12.5, 14, 15.5,....

The first term is defined as a = 12.5,

with a common difference of d = 1.5 cm.

Thus, the height of x stacked cups is given by

h(x) = a+(x-1)d = 12.5 + (x-1)1.5 = 1.5x + 11

As per the problem,

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Another project on Kickstarter for an iPad stylus raised 1,253% of their goal, raising a total of $313,490 from 7,511 supporters
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The initial goal was $25019.154.

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Assuming the original goal is denoted as x.

As stated

Another Kickstarter initiative for an iPad stylus secured 1,253% of its target, accumulating a total of $313,490.

1253% can be expressed as a decimal.

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x = \frac{313490}{12.53}

x = $ 25019.154

This means the initial goal stands at $25019.154.

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