Typically, the graph will have a labeled line such as f(x) = ... To find f(3), identify 3 on the x-axis, then trace vertically to the graph line and read the corresponding y-value.
Answer:
- 128 Superscript StartFraction 3 Over x EndFraction
- (4RootIndex 3 StartRoot 2 EndRoot)x
- (4 (2 Superscript one-third Baseline) ) Superscript x
Step-by-step explanation:
Considerando la ecuación dada ![(\sqrt[3]{128} )^{x}\\](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C)
De acuerdo con una de las leyes de índices,
![(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}](https://tex.z-dn.net/?f=%28%5Csqrt%5Ba%5D%7Bm%7D%20%29%5E%7Bb%7D%5C%5C%3D%20%28%5Csqrt%7Bm%7D%29%5E%5Cfrac%7Bb%7D%7Ba%7D)
Aplicando esta ley a la pregunta;
![(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C%20%3D%20%7B128%7D%20%5E%5Cfrac%7Bx%7D%7B3%7D%5C%5C%20%5C%5C%3D%20%28%5Csqrt%5B3%5D%7B64%2A2%7D%29%5E%7Bx%7D%20%5C%5C%20%3D%20%284%5Csqrt%5B3%5D%7B2%7D%29%5E%7Bx%7D%20%5C%5C%3D%20%284%282%5E%7B1%2F3%7D%20%29%5E%7Bx%7D%20%29)
<pLos siguientes son ciertos de acuerdo con el cálculo presentado
128 Superscript StartFraction 3 Over x EndFraction
(4RootIndex 3 StartRoot 2 EndRoot)x
(4 (2 Superscript one-third Baseline) ) Superscript x
Response:
a)12 b)12 c)36
Detailed steps:
a) Identify the least common multiple. The quantity of marbles corresponds to that value multiplied by n (with n representing an integer)
b) The least common multiple is calculated as 4*3=...
c)12*3 =?
Afterward, simply divide by 2, 3, and 4 to find the solution
Answer:
Robyn's model is logical, while Mark's is illogical.
Step-by-step explanation:
This question doesn't require calculations. What we need to do is analyze each model logically.
Mark's
Mark's representation indicates 20 instead of 2, which signifies that 200 is ten times greater than 20, making it nonsensical.
Robyn's
Robyn's representation displays 2, suggesting that 200 is 100 times greater than 2, which is not only accurate but also reasonable since 100 * 2 equals 200.