Answer:
2(CH3)2N2H2 + 3N2O4 → 4N2 + 4H2O + 4CO2 + heat
Explanation:
- To balance chemical equations, coefficients are assigned to both reactants and products.
- This yields an equal count of atoms of each element on both sides of the equation.
- Balancing chemical equations ensures compliance with the law of conservation of mass.
- According to this law, the mass of reactants must equal the mass of products, achievable through balancing the equation.
- The application of coefficients 2, 3, 4, 4, 4 allows for an equal balance in the equation.
- Consequently, the balanced equation can be written as:
2(CH3)2N2H2 + 3N2O4 → 4N2 + 4H2O + 4CO2 + heat
Answer:
To break a single I-I bond, the wavelength of light required is 7.92 × 10⁻⁷ m
Explanation:
The energy needed to break one mole of iodine-iodine single bonds is 151 KJ
The energy necessary to rupture one iodine-iodine bond is calculated as (151 KJ/mol) / 6.02 × 10²³/mol = 2.51 × 10⁻²² KJ
or
2.51 × 10⁻¹⁹ J
Formula:
E = hc / λ
Where h is Planck's constant = 6.626 × 10⁻³⁴ js
c is the speed of light = 3 × 10⁸ m/s
λ
= wavelength
Solution:
E = hc / λ
λ = hc / E
λ = (6.626 × 10⁻³⁴ js × 3 × 10⁸ m/s ) / 2.51 × 10⁻¹⁹ J
λ = 19.878 × 10⁻²⁶ j.m / 2.51 × 10⁻¹⁹ J
λ = 7.92 × 10⁻⁷ m
Answer:
a) 
b) 1657 €
Explanation:
Hola,
a) En esta cuestión analizaremos el millón de litros de agua anualmente, dado que este dato nos permite calcular el calor necesario para calentar dicha cantidad, considerando que la densidad del agua es de 1 kg/L:
A continuación, utilizamos la entalpía de combustión del metano para determinar la cantidad en kilogramos necesaria, ya que la energía calórica perdida por el metano es equivalente a la energía obtenida por el agua:
b) En este supuesto, tenemos que, bajo condiciones normales de 1 bar y 273 K, el precio de 1 metro cúbico de metano es 0,45 €, lo que nos permite calcular las moles de metano en esas condiciones:
En consecuencia, los kilogramos de metano que se obtienen por 0,45 € son:
Finalmente, usando regla de tres:
0.715 kg ⇒ 0.45 €
2630 kg ⇒ X
X = (2630 kg x 0.45 €) / 0.715 kg
X = 1657 €
Regards.
First scenario:
IV: soda, gatorade, orange juice, and water
DV: state of the liquids listed above
Control: freezer and ice tray
Second scenario:
IV: laundry detergent, water
DV: cleanliness of the squares post-wash
Control: chocolate, cloth type, cloth squares
Third scenario:
IV: type of water used, pea plant
DV: growth of the pea plant
Control: pots and daily water amount for the plant
In a 100 g sample of the compound, there are 63.57 g of carbon, 6 g of hydrogen, 9.267 g of nitrogen, and 21.17 g of oxygen. First, convert these masses into moles (n) using the formula n = m/M, where M is the molar mass from the periodic table.
For carbon: 63.57 g C -> 63.57 g C / 12.01 g/mol = 5.29 moles C.
For hydrogen: 6 g H -> 6 g H / 1.008 g/mol = 5.95 moles H.
For nitrogen: 9.267 g N -> 9.267 g N / 14.01 g/mol = 0.6615 moles N.
For oxygen: 21.17 g O -> 21.17 g O / 16.00 g/mol = 1.32 moles O.
Thus, the mole ratio looks like this: C 5.29 H 5.95 N 0.6615 O 1.32.
Now, divide each value by the smallest number (1.32): C 4 H 4.5 N 0.5 O 1.
To eliminate fractions, multiply all values by 2, yielding C8H9N1O2.
Now, all numbers are integers! Hence, the empirical formula is C8H9NO2.
Although the empirical formula isn't always the same as the molecular formula, in this instance, it corresponds to acetaminophen.
