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professor190
1 month ago
15

1. Bailey wants to find out which frozen solid melts the fastest: soda, gatorade, or orange juice. She pours each of the three l

iquids into the empty cubes of an ice tray, along with a forth liquid, plain water. She then places the ice tray in the freezer over night. The next day, she pulls the ice tray out and sets each cube on its
own plate. She then waits and watches for them to melt. When the last part of the frozen liquid melts, she records the time.

Independent Variable:
Dependent Variable:
Control(s):
Constants:

--

2. Jack wants to find out which laundry detergent cleans the best. So, he takes a cotton sheet and cuts it up into equal squares. He stains four squares with chocolate. He washes one of each of the squares in each of the 3 detergents, and the final square is washed in plain water. For each wash load, he used: the same amount of water, the same amount of detergent, and the same temperature of water.

Independent Variable:
Dependent Variable:
Control(s):
Constants:

---

Maverick wants to find out whether or not Miracle Grow really makes plants grow faster. He takes two identical pots, puts ½ cup of dirt into each one, puts 3 pea plant seeds into each one, and tops each off with ½ cup more dirt. He waters the plants the same amount at the same time each day. The only difference is that one plant is watered with regular water, while the other is watered with water that has Miracle Grow in it.

Independent Variable:
Dependent Variable:
Controls(s):
Constants:
Chemistry
2 answers:
Alekssandra [3K]1 month ago
8 0

Answer:

Scientific investigations are conducted to evaluate hypotheses that involve three categories of variables: independent, dependent, and constant variables.

1. Independent variables: These can be controlled and adjusted during the experiment.

2. Dependent variables: These are assessed during the investigation.

3. Constant variables: These remain unchanged throughout the experiments but can influence the dependent variable.

4. Control: This is the sample that excludes the dependent variable.

Based on this, the variables identified in the examples are:

Case I

Independent variables-Time and night hours.

Dependent variables- state of the melting liquid  

Constant variable- freezer and ice tray

Control- plain water  

Case II

Independent variables- chocolate type, fabric type, fabric squares

Dependent variables- the type of detergent used

Constant variable- equal amounts of water, detergent, and temperature.

Control- square washed only with water.

Case III

Independent variables- Duration

Dependent variables- growth rate of the plant

Constant variable-  pots and the consistent water amount given

Control- pots without Miracle Grow watering

VMariaS [2.9K]1 month ago
4 0

First scenario:

IV: soda, gatorade, orange juice, and water

DV: state of the liquids listed above

Control: freezer and ice tray

Second scenario:

IV: laundry detergent, water

DV: cleanliness of the squares post-wash

Control: chocolate, cloth type, cloth squares

Third scenario:

IV: type of water used, pea plant

DV: growth of the pea plant

Control: pots and daily water amount for the plant

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Tems11 [2777]

Explanation:

The rate at which gases effuse is inversely related to the square root of their molar masses.

In this case, half of the helium (1.5 L) passed through the membrane in 24 hours. Therefore, we can calculate the effusion rate of He gas as follows.

          \frac{1.5 L}{24 hr}

            = 0.0625 L/hr

Given that the molar mass of He is 4 g/mol and for O_{2} it is 32 g/mol.

Now,

   \frac{\text{Rate of He}}{\text{Rate of Oxygen}} = \sqrt{\frac{32}{4}

                               = 2.83

Thus, the effusion rate of O_{2} = \frac{\text{Rate of He}}{2.83}

                       = \frac{0.0625 L/hr}{2.83}

          Rate of O_{2} = 0.022 L/hr.

This implies that 0.022 L of O_{2} gas will effuse in one hour.

Consequently, to find the duration needed for 1.5 L of O_{2} gas to effuse, we calculate as follows.

         \frac{1.5 L}{0.022 L/hr}

                = 68.18 hours

Thus, we can conclude that it will require 68.18 hours for half of the oxygen to effuse through the membrane.

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1 month ago
"The compound K2O2 also exists. A chemist can determine the mass of K in a sample of known mass that consists of either pure K2O
lorasvet [2795]

Answer:

Indeed, the chemist is capable of identifying the compound present in the sample.

Explanation:

In one mole of K₂O, potassium has a mass of 2 × 39.1 g = 78.2 g, while the total mass of K₂O is 94.2 g. The mass ratio of K compared to K₂O is calculated as 78.2 g / 94.2 g = 0.830.

For 1 mole of K₂O₂, potassium's mass remains the same at 78.2 g, but the total mass of K₂O₂ is 110.2 g. The mass ratio of K to K₂O₂ then equates to 78.2 g / 110.2 g = 0.710.

When the chemist measures the mass of K in relation to the overall sample, the mass ratio can be computed.

  • If the mass ratio is 0.830, then it indicates a pure K₂O compound.
  • If the mass ratio is 0.710, it indicates a pure K₂O₂ compound.
  • If the mass ratio falls outside of 0.830 or 0.710, the sample is assessed to be a mixture.
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2 months ago
No amino acid molecule by itself can speed up or catalyze reactions between other molecules; however, when amino acids are joine
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Answer:

This indicates that the enzyme is a type of protein.

Explanation:

It is important to remember that proteins are composed of vast numbers of amino acids. Because these amino acids are tiny units, they cannot function as a catalyst on their own.

However, when they form a polymer, the protein enzyme will possess varying shapes, sizes, and both physical and chemical attributes differing from a single monomer.

Additionally, for proteins to function actively, a specific number of amino acids must combine to create a distinct shape suited to interact with another molecule, thus accelerating the chemical reaction and functioning as an enzyme.

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1 month ago
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You have a balloon filled with hydrogen gas which keeps it at a
lorasvet [2795]

The resulting temperature is 46.5°C.

Details:

According to Charles's law, the volume of gas, while maintaining constant pressure, correlates directly with temperature in Kelvin.

The formula representing Charles's law is expressed as follows:

$\frac{V}{T} = constant

$\frac{V1}{T1} = \frac{V2}{T2}

We need to determine T2, thus:

$T2 = \frac{V2T1}{V1}

V1 = 736 ml = 0.736 L

T1 = 15 ° C

V2 = 2.28 L

Substituting the values gives us:

T2 = $\frac{2.28 \times 15}{0.736}

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It is evident that as the volume increases, the temperature also rises.

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1 month ago
A patient needs 40.0 mg of antibiotic per kilogram of body weight each day. If the patient weighs 55 kilograms.
VMariaS [2998]

Response:

2200 mg of antibiotic

Explanation:

The prescribed antibiotic dosage is 40 mg/kg of body weight.

For a patient weighing 55 kg, we calculate the dose of antibiotic as follows:

If we analyze 40/1000000, we can determine antibiotic allocation in kg per kg of weight

= 0.00004 kg of antibiotic for each kilogram

0.00004 multiplied by 55 (to find out the required amount for a 55 kg individual)

= 0.0022 kg

This 0.0022 figure converts to milligrams as follows

0.0022*10^6

= 2200 mg of antibiotic is indicated for a patient weighing 55 kg.

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14 days ago
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