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EastWind
9 days ago
10

If 75.0% of the isotopes of an element have a mass of 35.0 amu and 25.0% of the isotopes have a mass of 37.0amu what is the atom

ic mass of the element
A) 35.0amu
B)35.5amu
C)36.0amu
D)37.0amu
Chemistry
2 answers:
castortr0y [918]9 days ago
8 0
 <span>Calculating the average atomic mass involves a method similar to that of a weighted average. Follow this equation:

(mass1)(percentage1) + (mass2)(percentage2) = average atomic mass

(35.0)(0.75) + (37.0)(0.25) = average atomic mass

Ensure the percentages are represented in decimal format for accurate results.

While another response may be accurate, it lacks some clarity. Two potential answers can be dismissed immediately: 35.0 amu and 37.0 amu cannot represent the average. If the isotopes were mixed equally at 50%, then 36.0 amu would be the correct response; however, we have a 75/25 mix. Thus, only one answer remains viable.</span>
Alekssandra [962]9 days ago
6 0

Answer: It's B if you find the lengthy explanation unclear.

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For the chemical reaction HCN ( aq ) + KOH ( aq ) ⟶ H 2 O ( l ) + KCN ( aq ) HCN(aq)+KOH(aq)⟶H2O(l)+KCN(aq) write the net ionic
lions [985]

Answer:

H+(aq) + OH-(aq) ⟶ H2O(l)

Explanation:

Step 1: The balanced equation can be presented as

HCN(aq) + KOH(aq) ⟶ H2O(l) + KCN(aq)

H+(aq) + CN-(aq) + K+(aq) + OH-(aq) ⟶ H2O(l) + K+(aq) + CN-(aq)

Step 2: The net ionic equation is formed by removing the spectator ions — those that appear on both sides of the equation — leading us to the final representation:

H+(aq) + OH-(aq) ⟶ H2O(l)

4 0
3 days ago
Compaction is most significant as a lithification process for sedimentary rocks composed of sand-sized particles. True False
VMariaS [1037]

Response:

FALSE

Rationale:

Sedimentary rocks are defined as rocks formed through the processes of compaction and cementation. Initially, sediments derived from various locations must accumulate. Over time, these deposited sediments undergo substantial compaction due to the weight of the layers above. This process converts loose sediments into solid rock. This is the process through which sedimentary rocks, comprised of sand-sized particles, are formed. For instance, examples include Shale, Sandstone, and Mudstone.

Thus, both compaction and cementation are crucial in the formation of sedimentary rocks.

Therefore, the statement above is False.

8 0
5 days ago
Which procedure cannot be performed on a hot plate, requiring a Bunsen burner instead
Tems11 [839]

Answer: The process of heating a crucible to eliminate moisture from a hydrate.

Explanation:

The available choices are:

a. Heating a solvent to aid in the dissolution of a solute.

b. Heating a solid in isolation to remove moisture.

c. Bringing water to a boil for use in a water bath.

d. Heating a crucible to eliminate moisture from a hydrate.

Possible actions that can be done on a hot plate include:

a. Heating a solvent to assist a solute in dissolving.

b. Heating a solid in isolation to dry it.

c. Heating water to boiling for a water bath.

However, it's important to note that using a hot plate for heating a crucible to remove water from a hydrate is not advisable. Silica or ceramic materials are not meant to be heated on a hot plate.

Consequently, the correct procedure is heating a crucible to remove water from a hydrate.

4 0
11 days ago
Next we need to determine the mass of oleic acid in the monolayer. The concentration of the oleic acid/benzene solution is 0.02g
Alekssandra [962]

Response:

m=1x10^{-6}g

Clarification:

Hello,

In this scenario, since a single drop equates to 0.05 mL of the solution provided, with a concentration of 0.02 g/mL, the mass of oleic acid in one drop calculates to:

m=0.02\frac{g}{L}*0.05mL*\frac{1L}{1000mL}\\ \\m=1x10^{-6}g

Best wishes.

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