V = I * R, where V signifies voltage, I represents current, and R is resistance. According to Ohm's law, to determine the current through the wire, resistance is required. In theory, if the wire had zero resistance, it would lead to infinite current, which is not feasible. This negligible resistance could refer to the internal resistance of the battery rather than the wire itself.
Part a) The connection between the electric field and the magnetic field in an electromagnetic wave is

where
E signifies the strength of the electric field
B indicates the strength of the magnetic field
c represents the speed of light
Using the equation, we determine:

Part b) The text does not clarify the orientation of the magnetic field on the y-axis: I speculate it points in the y+ direction.
The direction of the electric field can be established using the right-hand rule, which states:
- the index finger shows the direction of E
- the middle finger indicates the orientation of B
- the thumb reveals the propagation direction of the wave
Because the wave propagates in the x+ direction, and the magnetic field in the y+ direction, we conclude that the electric field direction (index finger) must be z-.
U = 1794.005 × 10⁶ J. Explanation: Information provided indicates that the capacitance of the original capacitor is C = 1.27 F, and the potential difference applied to it is V = 59.9 kV, or 59.9 × 10³ V. The potential energy (U) for the capacitor is determined by the formula: U = (1/2) × C × V². Substituting the respective values, we find U = (1/2) × 1.27 × (59.9 × 10³)², resulting in U = 1794.005 × 10⁶ J.
Answer:
Explanation:
Within a duration of 60 seconds, six waves are observed.
With a total of 6 waves,
this equates to 3 wavelengths.
As a result,
the period for each wavelength is calculated as 60 divided by 3.
Thus, period = 20 seconds.
According to the frequency-period relationship,
f = 1 / T
f = 1 / 20
f = 0.05 Hz