Below are birds-eye views of six identical toy cars moving to the right at 2 m/s. Various forces act on the cars with magnitudes

Response:

216000 W or 216 kW

Details:

Power: This refers to the rate at which energy is utilized or consumed. The standard unit for power is the Watt (W).

In general,

Power = Energy/time

P = E/t........................ Equation 1.

However,

E = 1/2mv²..................... Equation 2

with m representing mass, and v indicating velocity.

Substituting equation 2 into equation 1,

P = 1/2mv²/t...................... Equation 3

Assuming flow rate (Q) = m/t,

Q = m/t................ Equation 4

Insert equation 4 into equation 3,

P = Qv²/2........................ Equation 5

Where Q stands for flow rate, v is velocity, and P denotes power.

Given: Q = 120 kg/s, v = 60 m/s

Plug these values into equation 5,

P = 120(60)²/2

P = 60(60)²

P = 60×3600

P = 216000 W.

Thus, the potential power generation of the water jet is 216000 W or 216 kW.

Answer:

Explanation:

In this scenario, we determine the initial velocity as follows:

The final velocity in this instance can be expressed as:

It is noted that transitioning from 7m/s to 13m/s takes 8 seconds. We can apply a specific kinematic equation to find the acceleration for the first part of the journey:

Solved for acceleration, we find:

For the subsequent route, we assume constant acceleration and that the train continues for 16 seconds, beginning with an initial velocity of 13m/s from the previous segment, allowing us to calculate the final speed via the following formula:

Substituting into the equation yields:

Respuesta:

Explicación:

Al analizar esta pregunta, considera el movimiento circular. Primero, determina la máxima fuerza que puede aplicarse al hilo. F = mg, entonces F = (10)(10) = 100 N. Luego, calcula la aceleración centrípeta de la masa de 0.5 kg, a = F/m, así que a = 100/.5 = 200 m/s². En la hoja de ecuaciones, usa la fórmula a (aceleración centrípeta) = v²/r, por lo que 200 = v²/2; por consiguiente, v = 20 m/s. ¡Espero que esto sea útil!

Explanation:

We are given that,

Mass of the rocket,

(a) The standard unit of mass is kilogram (kg). The conversion between slugs and kilograms is as follows:

1 slug = 14.59 kg

Thus,

Mass of the rocket, m = 3647500 kg

(b) The weight of the rocket can be expressed as:

W = m g

or

(c) If the rocket were on the moon, the gravitational acceleration on the moon is given as

Mass refers to the quantity of matter present in an object. Therefore, the mass of the rocket remains constant at 3647500 kg

The weight of the rocket on the moon would be,

W = 5872475 N

or

Thus, this is the final answer required.

Since the motorcycle was at a speed of 36 m/s prior to braking, that marks the initial velocity.

The motorcycle skidded 23m before coming to a full stop, indicating that

As it has ceased motion, the final velocity is zero.


We can apply the 'suvat' formula relevant to linear motion.


Substituting the aforementioned values allows us to find,









We can apply the formula

to calculate the time required for the motorcycle to stop.