If an electronic circuit experiences a loss of 3 decibels with an input power of 6 watts, what would its output power be, to the

Question

1 month ago

9

nearest watt?

2 answers:

kicyunya [3.2K] · Answer 1 · 2026-03-21T15:23:15+03:00

7 0

Answer:

The output power is 3 Watts

Explanation:

Given that a 3 dB loss occurs with an input of 6 Watts

We can conclude that

$3 dB = 10 Log\frac{P_{in}}{P_{out}}$

Now we understand that

$P_{in} = 6 Watt$

So ultimately

$0.30 = Log \frac{6}{P_{out}}$

Now we know

$P_{out} = 6 \times 10^{-0.30}$

$P_{out} = 3 Watt$

Thus, the output power will be 3 Watts

Yuliya22 [3.3K] · Answer 2 · 2026-03-21T15:23:30+03:00

Answer:

The output power of the circuit is 3 Watts.

Given:

a loss in decibels = 3 dB

Input power = 6 Watts

To find:

What is the output power?

Formula used:

Output power = Input power × loss in ratio

Solution:

3 dB loss corresponds to a ratio of 0.5

Output power can be calculated as follows:

Output power = Input power × loss in ratio

Output power = 6 × 0.5

Output power = 3 Watts

Therefore, the output power of the circuit is 3 Watts.