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Semmy
3 months ago
9

If an electronic circuit experiences a loss of 3 decibels with an input power of 6 watts, what would its output power be, to the

nearest watt?
Physics
2 answers:
kicyunya [3.2K]3 months ago
7 0

Answer:

The output power is 3 Watts

Explanation:

Given that a 3 dB loss occurs with an input of 6 Watts

We can conclude that

3 dB = 10 Log\frac{P_{in}}{P_{out}}

Now we understand that

P_{in} = 6 Watt

So ultimately

0.30 = Log \frac{6}{P_{out}}

Now we know

P_{out} = 6 \times 10^{-0.30}

P_{out} = 3 Watt

Thus, the output power will be 3 Watts

Yuliya22 [3.3K]3 months ago
4 0

Answer:

The output power of the circuit is 3 Watts.

Given:

a loss in decibels = 3 dB

Input power = 6 Watts

To find:

What is the output power?

Formula used:

Output power = Input power × loss in ratio

Solution:

3 dB loss corresponds to a ratio of 0.5

Output power can be calculated as follows:

Output power = Input power × loss in ratio

Output power = 6 × 0.5

Output power = 3 Watts

Therefore, the output power of the circuit is 3 Watts.

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