Paula is painting a henhouse. If a can of paint will cover 24 square feet, how many cans of paint does she need to buy? Explain

To determine this, we will apply the simple interest formula:
where
signifies the total amount.
indicates the principal amount.
represents the interest rate in decimal.
denotes the time period in years.

Investment A. The initial investment amount is $10,000, so . The investment period is 5 years, meaning . To express the interest rate in decimal, divide it by 100%

Now, we can substitute these values into our formula to find :




Investment B. , , and .




In conclusion, investment A will yield a greater value than investment B at the investment period's conclusion.

Answer:

At least 315

Step-by-step explanation:

A journalist intends to find the average annual salary of CEOs within the S&P 1,500. Due to time constraints, a sample is used.

Standard deviation of the sample (s) = 449300

Sample size = n

Permissible margin of error = 50000

Z critical value = 1.96

Thus, 1.96 times the standard error equals 50000.

Standard error equals 25510.20

Standard deviation divided by the square root of n = 25510.20

By simplifying, we can derive:

Thus, the minimum sample size required is 315.

Response:

The measure of mHLK is "(204)°".

Step-by-step breakdown:

Given values include:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

What is mHLK?

Now,

Utilizing the chord-chord angle formula, we find

Inserting the known values into the equation gives us

⇒  

By carrying out cross-multiplication, we arrive at

⇒  

⇒  

By subtracting "18x" from both sides, we obtain

⇒  

⇒  

Upon adding "2" to both sides, we end up with

⇒  

⇒  

⇒  

⇒  

By substituting the value of "x" into mHLK = (15x-36)°, we calculate

⇒ (15x-36)° = (15×16-36)°

⇒                = (240-36)°

⇒                = (204)°

Thus, mHLK = (204)°

Answer:

At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.

Step-by-step explanation:

A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.

The null and alternative hypotheses are:

The significance level is set at 0.10.

The sample mean recorded is 17, and the sample standard deviation is 5.37.

The degrees of freedom are calculated as df=(20-1)=19.

The t-statistic is:

The two-tailed P-value corresponding to t=1.67 is P=0.11132.

<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.

At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.

Answer: (97.98, 112.020)

Step-by-step explanation: We will create a 95% confidence interval for the average weight of melons.

Given the information, we determine that the critical value for the interval needs to be retrieved from a t distribution table due to the sample size being below 30 (specifically, 20), and we are provided with the sample standard deviation (s = 15 lb).

The parameters provided are:

Sample mean = x = 105 lb

Sample standard deviation = s = 15 lb

Sample size = n = 20

To establish the 95% confidence interval, we indicate that the level of significance is 5%.

The formula for the confidence interval is:

u = x + tα/2 × s/√n... for the upper limit

u = x - tα/2 × s/√n... for the lower limit.

tα/2 represents the critical value for the test (which will be determined using the t distribution table).

To derive tα/2, we look for the value based on the degrees of freedom (sample size - 1) against the significance level for a two-tailed test (α/2 = 0.025%) in a t distribution table.

For the upper limit, we calculate:

u = 105 + 2.093×15/√20

u = 105 + 2.093× (3.3541)

u = 105 + 7.020

u = 112.020.

<pfor the="" lower="" limit="" we="" find:="">

u = 105 - 2.093×15/√20

u = 105 - 2.093× (3.3541)

u = 105 - 7.020

u = 97.98

Confidence interval (97.98, 112.020)

</pfor>