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sveticcg
6 days ago
12

Uma empresa transporta armários para escritórios para uma localidade distante 425km. Seu custo é de R$2,10 por km rodado. Quando

os armários vão montados, a capacidade do veículo é de 60 unidades. Quando eles são desmontados a capacidade aumenta 6 vezes. Pede-se: 1- Qual o custo por armário montado? 2- Qual a economia por armário, quando esses são levados desmontados?
Mathematics
1 answer:
tester [3.9K]6 days ago
8 0

Answer:

1.  $14.88

2.  $12.40

Step-by-step explanation:

Translated into English:

A company is responsible for transporting office cabinets over a distance of 425km. The charge is R $ 2.10 for each kilometer journeyed. If the cabinets are assembled, the vehicle can carry 60 units. When taken apart, the capacity expands by 6 times. We need to determine: 1- The cost for each assembled cabinet? 2- The savings achieved per cabinet when they are disassembled.

Solution:

For 425 km at R $2.10 per km:

425 * 2.10 = $892.50 total expenditure

For the 60 assembled cabinets, the cost for each is calculated as:

Cost per assembled cabinet = 892.5/60 = $14.875, rounding to $14.88

When disassembled, the capacity becomes:

60 * 6 = 360

The cost per cabinet is then:

892.5/360 = $2.48

The savings indicate how much is saved compared to assembled cabinets:

14.88 - 2.48 = $12.40

Savings = $12.40

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In a GP if T3 = 18 and T6 = 486 Find:- T10
lawyer [4008]

Answer:

The 10th term in the geometric progression is 29.

Step-by-step explanation:

Given: In a geometric series, [T3 = 18] and [T6 = 486].

To find: The term [T10]?

Solution:

A geometric sequence takes the form [a, ar, ar^2,...]

Where, a represents the first term, and r denotes the common ratio.

The nth term is expressed as [Tn = a * r^(n-1)]

From the information provided: [T3 = a * r^2 = 18]

And [T6 = a * r^5 = 486]

By dividing the second equation by the first:

[(a * r^5) / (a * r^2)] = 486 / 18

[r^3 = 27]

Taking the cube root provides: r = 3.

Inserting r into one of the equations allows us to solve for a.

Substituting r gives: [T3 = a * r^2 = 18]

Thus, the first term is a = 2, and the common ratio is r = 3.

The 10th term in the geometric progression is computed as:

[T10 = a * r^(10-1)]

[Thus, T10 = 29.]

8 0
8 days ago
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Maggie is considering two investments. Investment A Investment B Principal $10,000 $8,000 Interest rate 3% 2.8% Time in years 5
Zina [3914]
To determine this, we will apply the simple interest formula: A=P(a+rt)
where
A signifies the total amount.
P indicates the principal amount.
r represents the interest rate in decimal.
t denotes the time period in years.

Investment A. The initial investment amount is $10,000, so P=10000. The investment period is 5 years, meaning t=5. To express the interest rate in decimal, divide it by 100%
r= \frac{3}{100} =0.03
Now, we can substitute these values into our formula to find A:
A=P(a+rt)
A=10000(1+0.03*5)
A=11500

Investment B. P=8000, t=15, and r= \frac{2.8}{100} =0.028.
A=P(a+rt)
A=8000(1+0.028*15)
A=11360

In conclusion, investment A will yield a greater value than investment B at the investment period's conclusion.
3 0
4 days ago
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A journalist wants to determine the average annual salary of CEOs in the S&P 1,500. He does not have time to survey all 1,50
Inessa [3907]

Answer:

At least 315

Step-by-step explanation:

A journalist intends to find the average annual salary of CEOs within the S&P 1,500. Due to time constraints, a sample is used.

Standard deviation of the sample (s) = 449300

Sample size = n

Permissible margin of error = 50000

Z critical value = 1.96

Thus, 1.96 times the standard error equals 50000.

Standard error equals 25510.20

Standard deviation divided by the square root of n = 25510.20

By simplifying, we can derive:

\sqrt{n} =\frac{449300}{25510.20} =17.752\\n=315\\

Thus, the minimum sample size required is 315.

8 0
12 days ago
Yoku is putting on sunscreen. He uses 2\text{ ml}2 ml2, start text, space, m, l, end text to cover 50\text{ cm}^250 cm 2 50, sta
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Answer:

13 Millilitres.

Step-by-step explanation:

Yoku applies 2ml to cover 50cm^2 of his skin.

He seeks to find out how many millilitres he needs to cover 325cm^2 of his body.

With 2ml, Yoku covers 50cm^2 of his skin

He will use \frac{2}{50}ml of sunscreen for covering 1cm^2 of his skin.

Thus:

For covering 325cm^2 of his body, he will require:

\frac{2}{50} X 325 ml\\=13ml

he would need 13 Millilitres.

7 0
4 days ago
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Stackable polystyrene cups have a height h1=12.5 cm. Two stacked cups have a height of h2=14 cm. Three stacked cups have a heigh
AnnZ [3877]

Answer:

Approximately 59 stacked cups.

Step-by-step explanation:

We have the following measurements:

Height of one cup = 12.5 cm,

Height of two cups stacked = 14 cm,

Height of three cups stacked = 15.5 cm,

...and so on.

This situation can be described by an arithmetic sequence,

12.5, 14, 15.5,....

The first term is defined as a = 12.5,

with a common difference of d = 1.5 cm.

Thus, the height of x stacked cups is given by

h(x) = a+(x-1)d = 12.5 + (x-1)1.5 = 1.5x + 11

As per the problem,

h(x) = 200

⇒ 1.5x + 11 = 200

⇒ 1.5x = 189

⇒ x = 59.3333333333 ≈ 59.

Therefore, you will need approximately 59 stacked cups.

3 0
3 days ago
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