Answer:
The change in entropy of the steam is 2.673 kJ/K
Explanation:
The mass of the liquid-vapor mixture is 1.5 kg
The mass in the liquid phase is calculated as 3/4 × 1.5 kg = 1.125 kg
The mass in the vapor phase is calculated as 1.5 - 1.125 = 0.375 kg
According to the steam tables
At a pressure of 200 kPa (200/100 = 2 bar), the specific entropy of steam is found to be 7.127 kJ/kgK
The entropy of steam can be calculated as specific entropy multiplied by mass = 7.127 × 0.375 = 2.673 kJ/K
Respuesta:
La temperatura máxima que se puede medir (en °C) es 14170.27°C
Explicación:
Los RTDs son termómetros compuestos de metales cuya resistencia aumenta con la temperatura.
Para un RTD de Clase A, l, Alpha = 0.00385.
La fórmula para el RTD es
Rt = Ro ( 1 + alpha x t)
Donde
Rt es la resistencia a la temperatura t°C,
Ro es la resistencia a 0°C
Alpha es un coeficiente de temperatura constante para un RTD de clase A.
Aquí, Rt = 1000ohms,
Ro se considera como Ra = 18Ohms
Por lo tanto,
1000 = 18 ( 1 + 0.00385t)
Dividiendo ambos lados por 18
1 + 0.00385t = 1000/18
0.00385t = 55.55 - 1
0.00385t = 54.55
t = 54.55/0.00385
t = 14170.27°C
For Deterministic Quicksort, which operates by selecting the first element as the pivot, consider a scenario where the pivot consistently divides the array into segments of 1/3 and 2/3 for all recursive calls. (a) The runtime recurrence for this case needs to be determined. (b) Use a recursion tree to justify that this recurrence resolves to Theta(n log n). (c) Provide distinct sequences of 4 and 13 numbers that prompt this behavior.
Answer:
t = 5.27 years
Explanation:
Firstly, the corrosion penetration rate is defined by the formula;
CPR = (KW)/(ρAt)
Where;
K = constant based on exposed area A.
W - mass lost over time
t- duration
ρ - density
A - area exposed
From the problem, we have;
W = 7.6kg or 7.6 x 10^(6) mg
CPR = 4 mm/yr
ρ = 4.5 g/cm³
Area = 800 cm²
K is a constant valued at 87.6cm
Rearranging the CPR formula to isolate t, we derive;
t = KW/(ρA(CPR))
t = (87.6 x 7.6 x 10^(6))/(4.5 x 800 x 4) = 46233.3 hours
The duration in question needs to be expressed in years.
Thus, converting hours to years;
There are 8760 hours in a year.
Therefore;
t = 46233.3/8760 = 5.27 years.
The maximum stress at the tip of the internal crack is calculated as 2872.28 MPa. Explanation: Details provided include the curvature radius of 3 × 10^-4 mm, a crack length of 5.5 × 10^-2 mm, and an applied tensile stress of 150 MPa. The equation used determines maximum stress based on these inputs.
