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1 month ago

Another focus of effective communication, according to Stephen Covey, is ensuring that:

Engineering

2 answers:

iogann1982 [368]1 month ago

4 0

Answer:

Stephen Covey emphasizes a principle crucial to effective interpersonal communication: first understand others before making yourself understood. This habit focuses on engaging in communication by listening attentively and truly comprehending the other person prior to sharing your own perspective.

Explanation:

iogann1982 [368]1 month ago

4 0

Answer:

prioritizing comprehension of others before sharing your own perspective

Explanation:

Stephen Covey emphasizes that the foundation of successful communication lies in grasping others' viewpoints prior to presenting your own ideas. Effective communication is a vital life skill, requiring integrity for it to be successful.

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Consider 1.0 kg of austenite containing 1.15 wt% C, cooled to below 727C (1341F). (a) What is the proeutectoid phase? (b) How

pantera1 [306]

Answer:

a) The phase before eutectoid is commonly referred to as cementite, with the chemical formula Fe₃C.

b) The total mass of ferrite obtained is 0.8311 kg.

The total cementite mass equals 0.1689 kg.

c) The total cementite mass accounts for 0.9343 kg.

Explanation:

Provided:

1 kg of austenite

a carbon content of 1.15 wt%

Cooled below 727°C

Questions:

a) Identify the proeutectoid phase.

b) Calculate the mass of total ferrite and cementite, Wf =?, Wc =?

c) Determine the mass of both pearlite and the proeutectoid phase, Wp =?

d) Create a schematic to illustrate the resulting microstructure.

a) The proeutectoid phase is referred to as cementite with the formula Fe₃C.

b) To find the total mass of formed ferrite:

$W_{f} =\frac{C_{cementite}-C_{2} }{C_{cementite}-C_{1} }$

With:

Ccementite = composition of cementite = 6.7 wt%

C₁ = composition of phase 1 = 0.022 wt%

C₂ = overall composition = 1.15 wt%

Inserting the values yields:

$W_{f} =\frac{6.7-1.15}{6.7-0.022} =0.8311kg$

For the total mass of cementite:

$W_{c} =\frac{C_{2}-C_{1}}{C_{cementite}-C_{1} } =\frac{1.15-0.022}{6.7-0.022} =0.1689kg$

c) The mass of pearlite:

$W_{p} =\frac{6.7-1.15}{5.94} =0.9343kg$

d) The diagram illustrates the different compositions: (pearlite, proeutectoid cementite, ferrite, eutectoid cementite)

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1 month ago

A solid circular shaft has a uniform diameter of 5 cm and is 4 m long. At its midpoint 65 hp is delivered to the shaft by means

grin007 [323]

A) τ_max = 59.139 x 10^(6) Pa. B) θ = 0.0228 rad.

6 0

14 days ago

A technician has been dispatched to assist a sales person who cannot get his laptop to display through a projector. The technici

mote1985 [299]

Answer:Ensure the correct cable is connected between the laptop and the projector. Check for HDMI inputs or 15-pin video output interfaces.

Also, make sure the laptop is set to project to the correct display output.

Explanation:

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1 month ago

Design a digital integrator using the impulse invariance method. Find and give a rough sketch of the amplitude response, and com

mote1985 [299]

50 μsec.

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10 days ago

The uniform dresser has a weight of 90 lb and rests on a tile floor for which the coefficient of static friction is 0.25. If the

Kisachek [356]

Answer:

a) $F = 736.065\,lbf$ , b) $\mu_{k} = 0.15$

Explanation:

a) The uniform dresser can be modeled using specific equilibrium equations:

$\Sigma F_{x} = F - \mu_{k}\cdot N = 0$

$\Sigma F_{y} = N-m\cdot g=0$

Following some algebraic manipulations, the formulated equation is derived:

$F = \mu_{k}\cdot m \cdot g$

$F = (0.25)\cdot (90\,lbm)\cdot (32.714\,\frac{ft}{s^{2}} )$

$F = 22.5\,lbf$

b) Similarly, the man can be represented by a set of equilibrium equations:

$\Sigma F_{x} = -F + \mu_{k}\cdot N = 0$

$\Sigma F_{y} = N-m\cdot g=0$

After some algebraic changes, the expression for the coefficient of static friction comes out as:

$\mu_{k} = \frac{F}{m\cdot g}$

$\mu_{k} = \frac{22.5\,lbf}{150\,lbf}$

$\mu_{k} = 0.15$

3 0

23 days ago