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nika2105
2 months ago
10

Another focus of effective communication, according to Stephen Covey, is ensuring that:

Engineering
2 answers:
iogann1982 [368]2 months ago
4 0

Answer:

Stephen Covey emphasizes a principle crucial to effective interpersonal communication: first understand others before making yourself understood. This habit focuses on engaging in communication by listening attentively and truly comprehending the other person prior to sharing your own perspective.

Explanation:

iogann1982 [368]2 months ago
4 0

Answer:

prioritizing comprehension of others before sharing your own perspective

Explanation:

Stephen Covey emphasizes that the foundation of successful communication lies in grasping others' viewpoints prior to presenting your own ideas. Effective communication is a vital life skill, requiring integrity for it to be successful.

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A well-insulated rigid tank contains 1.5 kg of a saturated liquid–vapor mixture of water at 200 kPa. Initially, three-quarters o
Daniel [329]

Answer:

The change in entropy of the steam is 2.673 kJ/K

Explanation:

The mass of the liquid-vapor mixture is 1.5 kg

The mass in the liquid phase is calculated as 3/4 × 1.5 kg = 1.125 kg

The mass in the vapor phase is calculated as 1.5 - 1.125 = 0.375 kg

According to the steam tables

At a pressure of 200 kPa (200/100 = 2 bar), the specific entropy of steam is found to be 7.127 kJ/kgK

The entropy of steam can be calculated as specific entropy multiplied by mass = 7.127 × 0.375 = 2.673 kJ/K

6 0
1 month ago
Read 2 more answers
Suppose we include the lead resistance in the calculation of temperature for a class A RTD. If R3 = 1000 ohms, Ra = 18 ohms, V0
alex41 [359]

Respuesta:

La temperatura máxima que se puede medir (en °C) es 14170.27°C

Explicación:

Los RTDs son termómetros compuestos de metales cuya resistencia aumenta con la temperatura.

Para un RTD de Clase A, l, Alpha = 0.00385.

La fórmula para el RTD es

Rt = Ro ( 1 + alpha x t)

Donde

Rt es la resistencia a la temperatura t°C,

Ro es la resistencia a 0°C

Alpha es un coeficiente de temperatura constante para un RTD de clase A.

Aquí, Rt = 1000ohms,

Ro se considera como Ra = 18Ohms

Por lo tanto,

1000 = 18 ( 1 + 0.00385t)

Dividiendo ambos lados por 18

1 + 0.00385t = 1000/18

0.00385t = 55.55 - 1

0.00385t = 54.55

t = 54.55/0.00385

t = 14170.27°C

5 0
24 days ago
Let Deterministic Quicksort be the non-randomized Quicksort which takes the first element as a pivot, using the partition routin
Daniel [329]
For Deterministic Quicksort, which operates by selecting the first element as the pivot, consider a scenario where the pivot consistently divides the array into segments of 1/3 and 2/3 for all recursive calls. (a) The runtime recurrence for this case needs to be determined. (b) Use a recursion tree to justify that this recurrence resolves to Theta(n log n). (c) Provide distinct sequences of 4 and 13 numbers that prompt this behavior.
3 0
1 month ago
A piece of corroded metal alloy plate was found in a submerged ocean vessel. It was estimated that the original area of the plat
Mrrafil [318]

Answer:

t = 5.27 years

Explanation:

Firstly, the corrosion penetration rate is defined by the formula;

CPR = (KW)/(ρAt)

Where;

K = constant based on exposed area A.

W - mass lost over time

t- duration

ρ - density

A - area exposed

From the problem, we have;

W = 7.6kg or 7.6 x 10^(6) mg

CPR = 4 mm/yr

ρ = 4.5 g/cm³

Area = 800 cm²

K is a constant valued at 87.6cm

Rearranging the CPR formula to isolate t, we derive;

t = KW/(ρA(CPR))

t = (87.6 x 7.6 x 10^(6))/(4.5 x 800 x 4) = 46233.3 hours

The duration in question needs to be expressed in years.

Thus, converting hours to years;

There are 8760 hours in a year.

Therefore;

t = 46233.3/8760 = 5.27 years.

8 0
1 month ago
What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 3 × 10-4
Kisachek [356]
The maximum stress at the tip of the internal crack is calculated as 2872.28 MPa. Explanation: Details provided include the curvature radius of 3 × 10^-4 mm, a crack length of 5.5 × 10^-2 mm, and an applied tensile stress of 150 MPa. The equation used determines maximum stress based on these inputs.
8 0
1 month ago
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