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BabaBlast
2 months ago
9

The most flexible and mobile method of supplying our need for mechanical energy has been the internal-__________ engine. (10 let

ters)
Engineering
2 answers:
alex41 [359]2 months ago
5 0
The response is combustion.
Daniel [329]2 months ago
4 0

Answer:

Combustion

Explanation:

This relates to an internal-combustion engine.

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Given num_rows and num_cols, print a list of all seats in a theater. Rows are numbered, columns lettered, as in 1A or 3E. Print
Viktor [391]

Answer:

This is the solution code in Python:

  1. alphabets = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J']
  2. user_input = input("Enter number of rows and columns: ")
  3. myArr = user_input.split(" ")
  4. num_rows = int(myArr[0])
  5. num_cols = int(myArr[1])
  6. seats = []
  7. for i in range(num_rows):
  8. row = []
  9. for j in range(num_cols):
  10. row.append(alphabets[j])
  11. seats.append(row)
  12. output = ""
  13. for i in range(len(seats)):
  14. for j in range(len(seats[i])):
  15. output += str(i + 1) + seats[i][j] + " "
  16. print(output)

Explanation:

Initially, we create a small list of alphabets from A to J (Line 1).

We then request the user to enter the number of rows and columns (Line 3). Given that the input comes as a string (e.g., "2 3"), we utilize the split() method to separate the numbers into individual items in a list (Line 4). The first item (row number) is assigned to variable num_rows, while the second item (column number) goes to num_cols.

Subsequently, we construct the seats list with a nested for-loop (Lines 10-15). Once the seats list is formed, another nested for-loop generates the required output string as per the question (Lines 19-21).

Finally, the output is printed (Line 23). For example, an input of 2 3 results in the output:

1A 1B 1C 2A 2B 2C

8 0
3 months ago
A cylinder in space is of uniform temperature and dissipates 100 Watts. The cylinder diameter is 3" and its height is 12". Assum
Kisachek [356]

Answer:

Temperature T = 394.38 K

Explanation:

The full solution and detailed explanation regarding the above question and its specified conditions can be found below in the accompanying document. I trust my explanation will assist you in grasping this particular topic.

7 0
2 months ago
Write cout statements with stream manipulators that perform the following:
grin007 [323]

Answer:

A)cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B)cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C)cout<<fixed<<5.789E12;

D)cout<<left<<setw(7)<<67;

Explanation:

Stream Manipulators are special functions for use with the insertion (<<) and extraction (>>) operators on C++ stream objects, while the 'cout' statement outputs content to the standard output device in C++ programming.

setw: specifies the minimum width of the output field

setprecision: defines the number of decimal places for floating-point value formatting.

fixed: sets the format flag for floating-point streams.

left: left-aligns the output.

A) This statement shows the number 34.789 in a field that provides eight character spaces with two decimal precision. cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B) Here, the number 7.0 is displayed within six spaces with three decimal precision. cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C) This command prints 5.789e+12 in fixed-point format.  cout<<fixed<<5.789E12;

D) This statement left-aligns the number 67 across a field of six spaces. cout<<left<<setw(7)<<67;

7 0
2 months ago
6.15. In an attempt to conserve water and to be awarded LEED (Leadership in Energy and Environmental Design) certification, a 20
Viktor [391]

Explanation:

At a temperature of 33^{\circ} C and relative humidity of 86%, the humidity ratio stands at 0.0223 with a specific volume of 14.289.

At a temperature of 33^{\circ} C and relative humidity of 40%, the humidity ratio is 0.0066 while the specific volume is 13.535.

To determine the mass of air, the following formula can be used:

\begin{aligned}m _{1} &=\frac{ v }{ v }(1- w ) \\&=\frac{1 \times 10^{5}}{13.535}(1-0.0066) \\&=7339.49 lb / min \\v _{ a } &=\frac{ m _{1} v }{(1- w )} \\v _{ a } &=\frac{7339.49 \times 14.289}{(1-0.0223)} \\v _{ a } &=107266.0 ft ^{3} / min\end{aligned}

Now, we will calculate the volume

\begin{aligned}m _{ w } &=\frac{ v _{ a }}{ v _{ a }} w _{ a }-\frac{ v _{ i }}{ v _{ i }} w _{ i } \\&=\frac{107266.0}{14.289} \times 0.0223-\frac{100000}{13.535} \times 0.0066 \\&=118.64 lb / min\end{aligned}

The duration required to fill the cistern can be determined with the equation:

Time \(=\frac{\text { cistern volume }}{\text { removal water perminute volume }}\)

By substituting the values into the preceding formula, we find:

\(\frac{\left(15 \times 10^{3} L\right) \times\left(0.0353147 ft ^{3} / L \right)}{(118.641 b / min ) \times\left(\frac{1}{62.41 lb / ft ^{3}}\right)}\)\\\(=279.09\) minutes\\\(=4.65\) hours.

Thus, the hours necessary to fill the cistern amount to 4.65 hours.

3 0
2 months ago
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