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BabaBlast
15 days ago
9

The most flexible and mobile method of supplying our need for mechanical energy has been the internal-__________ engine. (10 let

ters)
Engineering
2 answers:
alex41 [274]15 days ago
5 0
The response is combustion.
Daniel [215]15 days ago
4 0

Answer:

Combustion

Explanation:

This relates to an internal-combustion engine.

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You want to determine whether the race of the defendant has an impact on jury verdicts. You assign participants to watch a trial
grin007 [219]

Response:

The confidence scale is an ordinal measurement scale

Clarification:

An ordinal measurement scale is utilized for assessing attributes that can be ranked or ordered, yet the intervals in between attributes lack quantitative meaning. In this scenario, the scale utilized was from 1 to 7, where "1" signifies that the defendant's race has little impact on jury verdicts, and "7" indicates a strong impact of race on such verdicts. For instance, in a survey measuring customer satisfaction for a product, a "1" indicates great dissatisfaction, while "10 " denotes highest satisfaction. In the first instance, it would be incorrect to assert that the difference between a rating of 1, which implies "not at all," and perhaps a 3, is equivalent to the gap between a 5 and a 7, as these numbers merely serve as labels devoid of quantifiable value.

Other types of measurement levels include:

1. Nominal: This is the most straightforward measurement level, employed primarily for categorizing attributes. An example would be gathering data on gender, with categories such as male, female, and transgender.

2. Interval: An interval scale is used when the distances between two attributes hold meaning, but a true zero point is absent from the scale.

3. Ratio: This level combines all three previously mentioned measurements, serving to categorize, show ranking, maintain meaningful distances between attributes, and possess a true zero point. A typical example is measuring temperature using a Celsius thermometer, which has a true zero at 0°C, and the intervals between 5°C and 10°C are equivalent to those between 10°C and 15°C.

6 0
4 days ago
Gold and silver rings can receive an arc and turn molten. True or False
grin007 [219]
That statement is incorrect!
The claim is untrue
8 0
1 month ago
Read 2 more answers
A well-insulated rigid tank contains 1.5 kg of a saturated liquid–vapor mixture of water at 200 kPa. Initially, three-quarters o
Daniel [215]

Answer:

The change in entropy of the steam is 2.673 kJ/K

Explanation:

The mass of the liquid-vapor mixture is 1.5 kg

The mass in the liquid phase is calculated as 3/4 × 1.5 kg = 1.125 kg

The mass in the vapor phase is calculated as 1.5 - 1.125 = 0.375 kg

According to the steam tables

At a pressure of 200 kPa (200/100 = 2 bar), the specific entropy of steam is found to be 7.127 kJ/kgK

The entropy of steam can be calculated as specific entropy multiplied by mass = 7.127 × 0.375 = 2.673 kJ/K

6 0
1 day ago
Read 2 more answers
A thin-film gold conductor for an integrated circuit in a satellite application is deposited from a vapor, and the deposited gol
mote1985 [204]

Answer:

Explanation:

The equilibrium vacancy concentration can be described by:

nv/N = exp(-ΔHv/KT),

where T is the temperature at which vacancies form,

K = Boltzmann's constant,

and ΔHv = enthalpy of vacancy formation.

Rearranging this equation to express temperature allows you to calculate it using the provided values. A detailed breakdown of the process is included in the attached file.

5 0
19 days ago
You are working in a lab where RC circuits are used to delay the initiation of a process. One particular experiment involves an
pantera1 [220]

Answer:

t'_{1\2} = 6.6 sec

Explanation:

The half-life for the specified RC circuit can be expressed as

t_{1\2} =\tau ln2

where [/tex]\tau = RC[/tex]

t_{1\2} = RCln2

Given t_{1\2} = 3 sec

The circuit has a resistance of 40 ohms, and by adding a new resistor of 48 ohms, the total resistance becomes 40 + 48 = 88 ohms.

Thus, the new half-life is

t'_{1\2} =R'Cln2

Now, divide equation 2 by 1

\frac{t'_{1\2}}{t_{1\2}} = \frac{R'Cln2}{RCln2} = \frac{R'}{R}

t'_{1\2} = t'_{1\2}\frac{R'}{R}

After substituting all values, we can calculate the revised half-life

t'_{1\2} = 3 * \frac{88}{40} = 6.6 sec

t'_{1\2} = 6.6 sec

7 0
25 days ago
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