What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 3 × 10-4

Answer:

I am unsure what it entails?

There are five distinct types of fire extinguishers, each identifiable by specific color codes.

Red - Water-based

Creme - Foam-based

Blue - Powder-based

Black - CO2 or carbon dioxide-based

Yellow - Wet chemical-based

The type of fire extinguisher required is determined by the class of fire being dealt with.

Class A - Combustible materials (e.g., paper, wood) Recommended extinguishers - Red, Creme, Blue, and Yellow. (Avoid using Black)

Class B - Flammable liquids (e.g., paint, petrol, alcohol) Recommended extinguishers - Creme, Blue, and Black. (Avoid using Red or Yellow)

Class C - Flammable gases (e.g., butane, methane) Recommended extinguishers - Blue (Avoid using Red, Creme, Black, or Yellow)

Class D - Flammable metals (e.g., lithium, potassium) Recommended extinguishers - Blue (Avoid using Red, Creme, Black, or Yellow)

Class F - Deep fat fryers (e.g., chip pans) Recommended extinguishers - Yellow (Avoid using Red, Creme, Blue, or Black)

Electrical - any kind of electrical device

(e.g., computers, generators) Recommended extinguishers - Blue and Black (Avoid using Red, Creme, or Yellow)

Answer:

153.2 J

Explanation:

Let’s first identify our known variables:

mass (m) of the block = 10 kg

distance slid down (i.e., displacement) = 2 m

coefficient of kinetic friction (μk) = 0.2

In the following diagram, if we analyze the force component directed along the displacement, we find

Fcos 40°

100 (cos 40°)

76.60 N

The work done by the frictional force is then calculated as:

W = × displacement

W = 76.60 × 2

W = 153.2 J

Therefore, the work done by the frictional force equals 153.2 J

Answer:

a) v₂ = 26.6 ft/s

b) v₂ = 31.9 ft/s

Explanation:

a) Applying the principle of energy conservation for the soccer arm from the point of impact to its lowest point:

The ball's velocity in the tangential direction is given by:

v₂*sinθ = v₁*sin30

With the values:

if v₁ = 0

θ = 0º

The restitution coefficient is:

where O=θ

The aggregate momentum equation is:

, where O = θ

When we incorporate gravitational acceleration:

Isolating v₂ results in:

v₂ = 26.6 ft/s

b) To find the ball's velocity, we utilize:

v₂ * sinθ = v₁ * sin30

if v₁ = 10 ft/s

then v₂ * sinθ = 10 * sin30

thus sinθ = 5/v₂

The restitution coefficient remains:

where O = θ

Solving for v₂ yields:

v₂ = 31.9 ft/s

Answer:

90 L.atm

Explanation:

According to the provided details:

First pathway:

A( 3 atm, 20 L) → C ( 1 atm, 20 L) → D (1 atm, 50 L)

Second pathway:

A(3 atm, 20 L) → B( 3 atm, 50 L) → D ( 1 atm, 50 L)

As the number of moles is 1.00 moles

To calculate wAB;

A → B signifies the transformation is happening at a steady pressure;

Thus,

wAB = pressure multiplied by the change in volume

wAB = P(V₂ - V₁)

wAB = 3 atm (50 L - 20 L)

wAB = 3 atm (30 L)

wAB = 90 L.atm