Response:
Tube 2: 8.26 * 10^-3; Tube 4: 6.83 * 10^-5
Explanation:
For the MIC test's serial dilutions, each tube should contain an equal volume of nutrient broth: 5.0 mL, while the agent's volume per dilution must also match: 0.5 mL.
The serial dilution process followed was:
- Tube 1: 0.5/5.5
- Tube 2: 0.5 mL from tube 1 was diluted with 5.0 mL of broth, resulting in a dilution of tube 2 as (1:11) * (1:11) = (0.5/5.5) * (0.5/5.5) = 1:121 = 8.26 * 10^-3
- Tube 3: similar calculations yield 1:1331 = 7.51 * 10^-4
- Tube 4: yields 1:14641 = 6.83 * 10^-5.
Answer:
The answer is 7160 cm
Explanation:
Given Data
Diameter = 1 mm
Length =?
Quantity of gold = 1 mol
Density = 17 g/cm³
Steps
1.- Obtain the atomic mass of gold
Atomic mass = 197 g
This means 197g ------------ 1 mol
2.- Find the volume of the wire
Density = mass/volume
Volume = mass/density
Volume = 197/17
Volume = 5.7 cm³
3.- Calculate the wire length
Volume = πr²h
Rearranging for h
h = volume / πr²
Radius = 0.05 cm
Substituting values
h = 5.7/(3.14 x 0.05²)
h = 5.7 / 0.0025
h = 7159.2 cm ≈ 7160 cm
Answer:
The response is provided below.
Explanation:
Numerous aspects can influence the actual results of titration. These factors vary from human error to misjudging measurements, a researcher's interpretation of color changes, and improper techniques during the experimental procedure.
Thus, to mitigate these errors, researchers must engage thoroughly throughout experimentation, and employing gross readings can assist in reducing mistakes when determining the final titre value.
Answer:
The integer value of x in the hydrate is 10.
Explanation:

Molar concentration of the solution = 0.0366 M
Volume of the solution = 5.00 L
Moles of hydrated sodium carbonate = n


Weight of hydrated sodium carbonate = n = 52.2 g
Molar mass of hydrated sodium carbonate = 106 g/mol + x * 18 g/mol



By solving for x, we arrive at:
x = 9.95, approximating to 10
The integer x in the hydrate equals 10.
Answer: The right choice is (c) application of both a mobile phase and a stationary phase.
Explanation:
Chromatography: This refers to a technique for separating a mixture where the mixture is distributed between two phases at varying rates, one being stationary and the other moving.
Mobile phase: The component in which the mixture is dissolved is referred to as the mobile phase.
Stationary phase: This is an adsorbent medium that remains in place while a liquid or gas passes over its surface, thus remaining stationary.
Consequently, a key characteristic of any chromatography technique involves utilizing both a mobile and a stationary phase.