The concentration of the drug stock solution measures 1.5 × 10^-9 M, indicating that there are 1.5 × 10^-9 moles of the drug for every liter of solution.
To determine the number of moles in 1 ml (which is 1 × 10^-3 L), calculate: 1 × 10^-3 L × 1.5 × 10^-9 moles/1 L = 1.5 × 10^-12 moles.
Each mole of the drug consists of 6.023 × 10^23 molecules.
Thus, for 1.5 × 10^-12 moles of the drug, the corresponding number of molecules is:
1.5 × 10^-12 moles × 6.023 × 10^23 molecules/1 mole = 9.035 × 10^11 molecules.
The total number of cancer cells is 2.0 × 10^5.
The ratio hence equals the drug molecules divided by the cancer cells:
9.035 × 10^11 / 2.0 × 10^5 = 4.5 × 10^6.
Answer:
THE MOLAR MASS OF XCL2 IS 400 g/mol
THE MOLAR MASS OF YCL2 IS 250 g/mol.
Explanation:
We derive the molar mass of XCl2 and YCl2 by recalling the molar mass formula when both mass and the number of moles are known.
Number of moles = mass / molar mass
Molar mass = mass / number of moles.
For XCl2,
mass = 100 g
number of moles = 0.25 mol
Thus, molar mass = mass / number of moles
Molar mass = 100 g / 0.25 mol
Molar mass = 400 g/mol.
For YCl2,
mass = 125 g
number of moles = 0.50 mol
Molar mass = 125 g / 0.50 mol
Molar mass = 250 g/mol.
Accordingly, the molar masses for XCl2 and YCl2 are 400 g/mol and 250 g/mol, respectively.
Hello, in this situation, the chemical reaction occurring is as follows: Next, we will ascertain the limiting reactant by calculating the moles of magnesium oxide produced from 3.86 g of magnesium and 155 mL of oxygen using the given mole ratios of 2:1:2 and applying the ideal gas equation, demonstrating that oxygen is the limiting reactant because it generates the least magnesium oxide. Subsequently, we determine the mass of magnesium consumed solely by the oxygen.
