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1 month ago

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A cart moves along a track at a velocity of 3.5 cm/s. when a force is applied to the cart, its velocity increases to 8.2 cm/s. i

f it takes the cart 1.5 seconds to reach 8.2 cm/s, what is the acceleration of the cart? round your answer to the nearest tenth.

2 answers:

inna [3.1K]1 month ago

5 0

In physics, acceleration describes how an object's velocity changes over time. Whenever the speed of an object shifts, it's considered to be accelerating. To calculate acceleration here:

acceleration = (8.2 - 3.5) / 1.5 = 3.1 m/s²

I trust this answers your question.

inna [3.1K]1 month ago

5 0

According to the given definition, we need to use the formula:

$vf = a * t + vo$

Where,

vf: final velocity

a: acceleration

t: time duration

vo: initial velocity

From this, we isolate the acceleration variable.

The resulting formula is:

$a = \frac{vf-vo}{t}$

Substituting the given numbers, we get:

$a = \frac{8.2-3.5}{1.5}$

When rounded to one decimal place, the value becomes:

$a = 3.1 \frac{cm}{s^2}$

Solution:

The cart’s acceleration is:

$a = 3.1 \frac{cm}{s^2}$

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