Ask question

Ask question

All categories

3 months ago

15

A cart moves along a track at a velocity of 3.5 cm/s. when a force is applied to the cart, its velocity increases to 8.2 cm/s. i

f it takes the cart 1.5 seconds to reach 8.2 cm/s, what is the acceleration of the cart? round your answer to the nearest tenth.

2 answers:

inna [3.1K]3 months ago

5 0

In physics, acceleration describes how an object's velocity changes over time. Whenever the speed of an object shifts, it's considered to be accelerating. To calculate acceleration here:

acceleration = (8.2 - 3.5) / 1.5 = 3.1 m/s²

I trust this answers your question.

inna [3.1K]3 months ago

5 0

According to the given definition, we need to use the formula:

$vf = a * t + vo$

Where,

vf: final velocity

a: acceleration

t: time duration

vo: initial velocity

From this, we isolate the acceleration variable.

The resulting formula is:

$a = \frac{vf-vo}{t}$

Substituting the given numbers, we get:

$a = \frac{8.2-3.5}{1.5}$

When rounded to one decimal place, the value becomes:

$a = 3.1 \frac{cm}{s^2}$

Solution:

The cart’s acceleration is:

$a = 3.1 \frac{cm}{s^2}$

You might be interested in

Isabella drops a pen off her balcony by accident while celebrating the successful completion of a physics problem. assuming air

Yuliya22 [3333]

U = 0, the initial vertical velocity

Ignoring air resistance, with g set to 9.8 m/s².

The duration, t, required for the pen to reach a vertical speed of 19.62 m/s can be calculated with
19.62 m/s = 0 + (9.8 m/s²)*(t s)
t = 19.62/9.8 = 2.00 s

Result: 2.0 s

8 0

2 months ago

James Cameron piloted a submersible craft to the bottom of the Challenger Deep, the deepest point on the ocean's floor, 11,000 m

serg [3582]

Answer:

$4.1\cdot 10^8 N$

Explanation:

To begin with, we must determine the pressure acting on the sphere, which is calculated using:

$p=p_0 + \rho g h$

where

$p_0 =1.01\cdot 10^5 Pa$ denotes the atmospheric pressure

$\rho = 1000 kg/m^3$ represents the density of the water

$g=9.8 m/s^2$ signifies the acceleration due to gravity

$h=11,000 m$ indicates the depth

By substituting these values,

$p=1.01\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(11,000 m)=1.08\cdot 10^8 Pa$

The sphere's radius is calculated as r = d/2 = 1.1 m/2 = 0.55 m

Thus, the sphere's total surface area can be expressed as

$A=4 \pi r^2 = 4 \pi (0.55 m)^2=3.8 m^2$

Consequently, the inward force acting on the sphere equals

$F=pA=(1.08\cdot 10^8 Pa)(3.8 m^2)=4.1\cdot 10^8 N$

8 0

2 months ago

Read 2 more answers

A 0.2-kg steel ball is dropped straight down onto a hard, horizontal floor and bounces straight up. The ball's speed just before

Ostrovityanka [3204]

Answer:

Explanation:

Provided:

mass of the steel ball $m=0.2\ kg$

initial velocity of the ball $u=10\ m/s$

Final velocity of the ball $v=-10\ m/s$ (moving upwards)

The impulse given is determined by the change in the momentum of the object.

<ptherefore the="" impulse="" j="" is="" defined="" by="">

$J=\Delta P$

$\Delta P=m(v-u)$

$\Delta P=0.2(-10-10)$

$\Delta =-4\ N-s$

Thus, the magnitude of the Impulse is 4 N-s.

</ptherefore>

7 0

2 months ago

Read 2 more answers

A car traveling at 70 mph70 mph down the interstate collides with a bug trying to cross the highway. Which of the following stat

Sav [3153]

The force exerted by the car on the bug is identical to the force the bug applies back on the car.

5 0

1 month ago

In the past, salmon would swim more than 1130 km (700 mi) to spawn at the headwaters of the Salmon River in central Idaho. The t

Keith_Richards [3271]

Answer:

$E_t_o_t_a_l=7.603MJ$

Explanation:

The overall energy expenditure of the salmon, which corresponds to its swimming upstream effort, $W$ , is linked to its specific mechanical power. $Mechanical \ power$ calculated per unit mass can be derived from the following equation:

$\frac{p}{m}=\frac{1}{m}|\frac{dW}{dt}|=2W/kg\\\frac{1}{2}|\frac{W}{22\times 24 \times 60\times 60}|=2\\\\W=7.603MJ$

As a result, the total energy utilized during the 22-day journey is 7.603 MJ

6 0

2 months ago