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AlladinOne
2 months ago
11

Pq=6x+25 and qr=16-3x; find pr

Mathematics
2 answers:
Svet_ta [12.7K]2 months ago
8 0

Answer:

PR equals 3x plus 41

Detailed solution:

We start with

PQ = 6x + 25

QR = 16 - 3x

Since Q lies between P and R, the segment PR is composed of PQ plus QR.

Therefore, we write

PR = PQ + QR

PR = (6x + 25) + (16 - 3x)

PR = 6x minus 3x plus 25 plus 16

PR = 3x + 41

Thus, PR equals 3x plus 41

Zina [12.3K]2 months ago
3 0

Given:\\\overline{PQ}=6x+25\\\overline{QR}=16-3x\\\\Finding:\overline{PR}

If \; Q \; is \; a \; point \; in \; between \; the \; line \; segment \; \overline{PR}, \; \\ then \; the \; distance \; of \; line \; segment \; \overline{PR} \; \\ can \; be \; found \; by \; adding \; line \; segment \; \overline{PQ} \; and \; \overline{QR}.

Using \; the \; concept \; \overline{PQ}+\overline{QR}=\overline{PR} \;,\\ we \; need \; to \; set \; up \; an \; equation \; given \; below:

\overline{PR} =6x+25 +16-3x\\\\Step \; 1: Grouping \; Like \; Terms\\\overline{PR} =6x-3x+25 +16\\\\Step \; 2: Combining \; Like \; Terms\\\overline{PR} =3x+41

Заключение:

\overline{PR} \; is \; represented \; the \; expression \; 3x +41

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Answer:

24

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Based on the logarithmic expressions given log_ax = 3, log_ay = 7, log_az = -2, we need to identify the value of log_a(\frac{x^3y}{z^4} )

from\ log_ax = 3, x = a^3\\\\from\ log_ay = 7,y = a^7\\\\from\ log_az = -2, z = a^{-2}By substituting x = a³, y = a⁷, and z = a⁻² into the logarithmic function log_a(\frac{x^3y}{z^4} ), we will derive;

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1 month ago
Which is true regarding the graphed function f(x)?
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Explanation:

Hello! Please remember to formulate complete questions to receive accurate answers. I will assume that the depicted function derives from:

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V(4,5)

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1 kilogram is equivalent to about 2.2 pounds. An orangutan weighs 142 pounds. What is its mass in kilograms? Round your answer t
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The weight of an orangutan is 64.5 kilograms

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It is stated that the orangutan's weight is 142 pounds

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