Answer:
First, we must calculate the slope
m=Y2-Y1/X2-X1
= 9 - (-6) / 12 - (-8)
= 15/20
= 3/4
Therefore, the equation with the slope of 3/4 is Y=3/4x
Answer:
Step-by-step explanation:
The prices he received quotes for are as follows: $663, $273, $410, $622, $174, $374
To begin, we will find the average.
Average = total of data points/ number of data points.
Total of data points =
663 + 273 + 410 + 622 + 174 + 374
= 2516
Total count = 6
Average = 2516/6 = 419.33
Standard deviation = √summation(x - m)^2/n
summation(x - m)^2/n = (663 - 419.33)^2 + (273 - 419.33)^2 + (410 - 419.33)^2 + (622 - 419.33)^2 + (174 - 419.33)^2 + (374 - 419.33)^2
= 179417.9334/6 = 29902.9889
Standard deviation = √29902.9889
= 172.9
Answer:
The increase is linear since the data indicates that sunflowers grew by a consistent amount each month.
Step-by-step explanation:
Referring to the table

Observe that the months progress incrementally (21-1, 3-2=1, 4-3=1).
Moreover
![17.2-15=2.2\ [\text{from month 1 to month 2}]\\ \\19.4-17.2=2.2\ [\text{from month 2 to month 3}]\\ \\21.6-19.4=2.2\ [\text{from month 3 to month 4}]](https://tex.z-dn.net/?f=17.2-15%3D2.2%5C%20%5B%5Ctext%7Bfrom%20month%201%20to%20month%202%7D%5D%5C%5C%20%5C%5C19.4-17.2%3D2.2%5C%20%5B%5Ctext%7Bfrom%20month%202%20to%20month%203%7D%5D%5C%5C%20%5C%5C21.6-19.4%3D2.2%5C%20%5B%5Ctext%7Bfrom%20month%203%20to%20month%204%7D%5D)
This indicates a linear increase in sunflower count, as the data shows a consistent monthly rise.
Answer:
The correct answer is;
A. 0.17
Step-by-step explanation:
Here are the provided details;
The average time taken for a cashier to handle an order, μ = 276 seconds
The deviation from the average, σ = 38 seconds
The z-score for an order processing time of x = 240 seconds can be calculated as follows;

Thus;

The resulting probability
P(z = -0.9474) = 0.17361
Hence, the estimated proportion of orders processed in under 240 seconds is roughly 0.17361 or 0.17 when rounded to two decimal places.
Response:
(A)
A symmetrical outcome occurs when both figures are identical.
The half section of the illustration is tilted downward; therefore, to achieve symmetry, we must shift the figure upwards.
Then, we reflect upon the inverted image.
Thus, we achieve reflectional and translational symmetry.