Answer:
0.40 feet
Step-by-step explanation:
For the first scenario, a 50-foot building casts a shadow of 1 foot. Let the angle of elevation of the sun from the shadow be denoted as θ.
Then:
Tan θ = 
Tan θ = 
Tan θ = 50
⇒ θ = 
50
= 88.8542
= 
The elevation angle is roughly .
For a 20-foot pole,
Tan θ =
Tan = 
x = 
= 0.4015
= 0.40 feet
The length of the pole's shadow is 0.40 feet.
Answer:
Question 13: For age groups y=1 and y=1.3, the response time is 8 microseconds.
Question 14: The club experienced losses between 11.28 and 4.88 years.
Step-by-step explanation:
Question 13:
The equation that gives the response rate R of 8 microseconds can be expressed as
Upon graphing this, we determine the solutions to be
We consider only positive values of y applicable in real-life scenarios.
Thus, the response is 8 microseconds solely for the age groups y=1 and y=1.3.
Question 14:
The football club incurs losses when 
Or
Graphing this inequality reveals the solutions to be
and 
As only positive values for t are relevant in practical situations, we accept the second solution.
Hence, the club faced losses during the years
Answer:
45 millas.
Explicación paso a paso:
Dado que la:
Distancia total recorrida = 390 millas
Tiempo total = 8 horas
Designando la distancia recorrida por la vía local como L
y la distancia recorrida por la carretera como H
Por la vía local,
La Velocidad = distancia/ tiempo
20 = L / T
T = L /20.... (1)
Por la carretera,
Distancia recorrida H = 390 - L
Sea el tiempo = t
La Velocidad = distancia/tiempo
60 = (390 - L)/t
t = ( 390 - L)/60
Pero el tiempo total = T + t
<pEs decir
8 = L/20 + (390 - L)/60
<pEl MCM en el lado derecho sería 60<p8 = ( 3L + 390 - L )/60<pMultiplicamos en cruz
480 = 2L + 390
<pAgrupamos los términos semejantes
2L = 480 - 390
2L = 90
L = 90/2
L = 45 millas.
<pAsí que la distancia que Minato recorrió por vías locales es de 45 millas
Utilize the details to create inequalities that reflect each limitation or requirement.
2) Label the
variables.
c: count of color copies
b: count of black-and-white copies
3)
Define each constraint:
i) <span>Printing a color copy requires 3 minutes while a black-and-white copy takes 1 minute.
</span><span>
</span><span>
3c + b</span><span>
</span><span>
</span><span>ii) He must print
a minimum of 6 copies ⇒
c + b ≥ 6</span><span>
</span><span>
</span><span>iv) Moreover, he must finish the prints within
12 minutes at most ⇒</span>
3c + b ≤ 12<span />
4) Additional limits include
c ≥ 0, and
b ≥ 0 (meaning
only non-negative counts are valid for each type of copy)
5) Here’s how to
illustrate that:
i) For 3c + b ≤ 12: draw the line representing 3c + b = 12 and shade the area above and to the right of this line.
ii) For c + b ≥ 6: draw the line c + b = 6 and shade the area below and to the left of this line.
iii) Given that c ≥ 0 and b ≥ 0, the relevant region is located in the
first quadrant.
iv) The concluding area is the
overlap of the previously mentioned shaded regions.v) The graph can be viewed in the attached figure.
