When the sun is at a certain angle in the sky, a 50-foot building will cast a -foot shadow. What is the length of the shadow in

12 m^2/h to cm^2/min

12 m^2/h × 1 h/60 min = 0.2 m^2/min

0.2 m^2/min × 10000 cm^2/1 m^2 = 2000 cm^2/min

2000 cm^2/min

Response:

2(3-n)+5.

Clarification:

Twice a number plus five equals three times the difference between that number and two. "More" indicates addition, hence twice the number is represented as multiplying N (or whatever variable) with the determination that it equals three times the reduction of that number and two.

Answer:

a) The distance covered halfway = 16.49 [m], while the displacement at that point = 10.5 [m]b)

The distance traveled increases

when the child finishes one lap around the track.

Step-by-step explanation:

a)

Distance is a scalar measurement

that indicates how much ground an object has traversed in motion. Contrarily, displacement is a vector measurement which describes how far an object is from its original position after moving.

In this scenario, the child travels halfway around the circular track from point 1 to point 2. We know that the circumference or perimeter of a circle can be calculated as 2*PI*radius. Since the child only covers half the distance, we need to divide the circumference by 2, leading to distance = PI*radius

The halfway distance = (PI)*(5.25) = 16.49 [m]

Considering the definition of displacement, it’s clear that the distance from point 1 to point 2 equals one diameter from the starting point:

The halfway displacement = D = 2*radius = 2(5.25) = 10.5 [m]

b) What occurs to the distance after the child completes one full circuit? The distance will increase since the child covers more ground during the full lap:

• The distance for one circuit = 2*(PI)*radius = 2(PI)(5.25) = 32.99 [m]

32.99 is greater than 16.49, confirming that the distance does indeed increase.

Answer: 47/59

Step-by-step explanation: