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stira
1 month ago
11

Layla is researching one of the outer planets. So far, she knows only that it is either a gas giant or an ice giant. Which two s

tatements best describe how Layla’s planet was formed?
A)Pressure near the Sun pushed the lighter elements far into space, where some of them could condense.
B)The planet accreted a significant amount of rocky material to form a planet larger than Earth.
C)The Sun’s extreme temperatures caused the planet’s gases to condense close to the Sun.
D)The planet experienced nuclear fusion within its core, surpassing temperatures found even on the Sun.
E)The planet developed a larger diameter than any of the four terrestrial planets located near the Sun.
Physics
2 answers:
Keith_Richards [3.2K]1 month ago
7 0

E) This planet has a greater diameter than any of the four terrestrial planets that orbit close to the Sun.

B) A substantial amount of rocky material accumulated to create a planet larger than Earth.

(Which two statements are the most accurate)

- A, C, and D simply do not make sense.

Yuliya22 [3.3K]1 month ago
6 0

Answer:

E) This planet has a greater diameter than any of the four terrestrial planets that orbit close to the Sun.

B) A substantial amount of rocky material accumulated to create a planet larger than Earth.

Explanation:

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A small cork with an excess charge of +6.0µC is placed 0.12 m from another cork, which carries a charge of -4.3µC.
serg [3582]

A) 16.1 N

The force of electricity acting between the corks can be calculated using Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where

k represents Coulomb's constant

q_1 = 6.0 \mu C=6.0 \cdot 10^{-6} C denotes the charge magnitude on the first cork

q_2 = 4.3 \mu C = 4.3 \cdot 10^{-6}C indicates the charge magnitude on the second cork

r = 0.12 m is the distance separating the corks

By inserting the values into the formula, we arrive at

F=(9\cdot 10^9 N m^2 C^{-2} )\frac{(6.0\cdot 10^{-6}C)(4.3\cdot 10^{-6} C)}{(0.12 m)^2}=16.1 N

B) Attractive

<pas per="" coulomb="" law="" the="" orientation="" of="" electric="" force="" between="" two="" charged="" entities="" relies="" on="" their="" charge="" signs.=""><pmore specifically="">

- when both are similarly charged (e.g. positive-positive or negative-negative), the force is repulsive

- when charges are of opposite signs (e.g. positive-negative), the resulting force is attractive

<pin this="" case="" we="" have="">

Cork 1 holds a positive charge

Cork 2 possesses a negative charge

<pthus the="" force="" acting="" between="" them="" is="" attractive.="">

C) 2.69\cdot 10^{13}

The total charge of the negative cork is

q_2 = -4.3 \cdot 10^{-6}C

<pwe understand="" that="" a="" single="" electron="" has="" charge="" of="">

e=-1.6\cdot 10^{-19}C

<pthe total="" charge="" of="" the="" negative="" cork="" arises="" from="" having="" n="" extra="" electrons="" so="" we="" can="" express="" it="" as="">

q_2 = Ne

<pafter solving="" for="" n="" we="" can="" determine="" the="" count="" of="" excess="" electrons:="">

N=\frac{q_2}{e}=\frac{-4.3\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=2.69\cdot 10^{13}

D) 3.75\cdot 10^{13}

The overall charge on the positive cork is

q_1 = +6.0\cdot 10^{-6}C

<pthe charge="" of="" a="" single="" electron="" is="" known="" to="" be="">

e=-1.6\cdot 10^{-19}C

<pthe total="" charge="" of="" the="" positive="" cork="" results="" from="" n="" excess="" electrons="" which="" can="" be="" depicted="" as="">

q_1 = -Ne

<pby calculating="" for="" n="" we="" derive="" the="" number="" of="" electrons="" cork="" has="" lost:="">

N=-\frac{q_1}{e}=-\frac{+6.0\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=3.75\cdot 10^{13}

</pby></pthe></pthe></pafter></pthe></pwe></pthus></pin></pmore></pas>
6 0
1 month ago
A rope connects boat A to boat B. Boat A starts from rest and accelerates to a speed of 9.5 m/s in a time t = 47 s. The mass of
ValentinkaMS [3465]

Answer: 339.148N

Explanation:

Given data:

Time (t) = 47s

Initial speed (U) = 0m/s

Final speed (V) = 9.5m/s

Mass of B = 540kg

Frictional force on B = 230N

Since both boats are linked, movement of A causes B to move as well.

What is the acceleration of boat A?

Applying the motion formula:

V = u + at

9.5 = 0 + a * 47

a = 9.5 / 47

a = 0.2021 m/s²

To determine the force necessary to accelerate boat B, as both boats experience the same force:

F = Mass * acceleration

F = 540 * 0.2021 = 109.14N

Given that there is a frictional force of 230N acting on boat B, the overall force (Tension) becomes:

Tension = frictional force + applied force = (109.14 + 230)N = 339.148N

7 0
1 month ago
-. What is the acceleration of 4 kg trolling bag pulled by a girl with a<br> force of 3 N?
inna [3103]

Answer:

Acceleration(a) = 0.75 m/s²

Explanation:

Given:

Force(F) = 3 N

Mass of object(m) = 4 kg

Find:

Acceleration(a)

Computation:

Force(F) = ma

3 = (4)(a)

Acceleration(a) = 3/4

Acceleration(a) = 0.75 m/s²

3 0
1 month ago
Dee is on a swing in the playground. the chains are 2.5 m long, and the tension in each chain is 450 n when dee is 55 cm above t
kicyunya [3294]
Referencing the diagram below, we can deduce from the geometry that x = 2.5 - 0.55 = 1.95 m, leading to cos θ = 1.95/2.5 = 0.78. Therefore, θ = cos⁻¹ 0.78 = 38.74°. According to the free body diagram, the tension in the chain measures 450 N. Here, F denotes the centripetal force and W signifies Dee's weight. The tension's components are as follows: Horizontal component = 450 sin(38.74°) = 281.6 N, directed to the left, and Vertical component = 450 cos(38.74°) = 351.0 N, directed upward. Answers: Horizontal: 281.6, directed left. Vertical: 351.0 N, directed upward.
8 0
19 days ago
When 999mm is added to 100m ______ is the result​
Keith_Richards [3271]

Answer:

The outcome of adding 999mm to 100m is 101m.

Explanation:

That's my belief.

6 0
1 month ago
Read 2 more answers
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