Recall this formula for a device operating in a direct current circuit:
P = IV
In this equation, P stands for the power emitted by the device, I signifies the current passing through the device, and V represents the voltage drop across it.
Using ampere for current and volt for voltage means that multiplying current by voltage gives you power measured in watts.
Explanation:
The formula for the electric field produced by an infinite sheet of charge is outlined below.
E =
where,
is the surface charge density
Following this, the formula for the electric force acting on a proton is given as:
F = eE
where, e is the charge of a proton
According to Newton's second law of motion, the overall force on the proton can be expressed as follows.
F = ma
a = 
= 
= 
According to kinematic equations, the proton's speed in the perpendicular direction can be described as follows.

= 
= 
= 683.974 m/s
Thus, the overall speed of the proton can be calculated as follows.
v' =
=

= 
= 1178.73 m/s
Consequently, we conclude that the proton's speed is 1178.73 m/s.
Response:
AB = 100 km; BC = 80 km; AC = 180 km
Time of arrival = 11:30
Reasoning:
1. Distance from A to B
(a) Duration of travel
Duration = 10:00 - 8:00 = 2.00 hours
(b) Distance
Distance = speed × time = 50 km/h × 2.00 h = 100 km
2. Distance from B to C
Distance = 80 km/h × 1 h = 80 km
3. Summary of Distances
AB = 100 km
BC = 80 km
AC = 180 km
4. Time of Arrival
Departure from A = 08:00
Travel duration to B = 2:00
Arrival at B = 10:00
Waiting time at B = 0:30
Departure from B = 10:30
Travel duration to C = 1:00
Arrival at C = 11:30
Answer:
The equivalent distance in kilometers is 4012 ×
km.
Explanation:
It's known that 1 millimeter converts to
meters. Then, 1 meter converts to
kilometers. Therefore, the conversion for 1 millimeter to kilometers can be stated as
1 mm =
m
1 m =
km
Thus, 1 mm =
×
km =
km.
Given the distance of 4012 mm, the corresponding distance in kilometers will be
4012 mm = 4012 ×
km.
The distance therefore is 4012 ×
km.
25.82 m/s
Explanation:
Given:
Force applied by the baseball player; F = 100 N
Distance the ball travels; d = 0.5 m
Mass of the ball; m = 0.15 kg
To find the velocity at which the ball is released, we will equate the work done with the kinetic energy involved.
It's important to recognize that work done reflects the energy the baseball player has used. Thus, the relationship can be represented as follows:
F × d = ½mv²
100 × 0.5 = ½ × 0.15 × v²
Solving gives:
v² = (2 × 100 × 0.5) / 0.15
v² = 666.67
v = √666.67
v = 25.82 m/s.