A 2.0-kg ball with an initial velocity of (4i + 3j) m/s collides with a wall and rebounds with a velocity of (–4i + 3j) m/s. Wha
1 answer:
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Answer:
Height (h) = 17 m
Velocity (v) = 18.6 m/s
Explanation: This problem can be solved using kinematic motion equations.
Given Data
Initial velocity (u) = 0
Acceleration (a) = g
Time (t) = 1.9 seconds
First, we calculate the height.
Then, we find the final velocity
The acceleration graph is a linear representation described by y=9.8, as it remains constant:
The velocity graph can be represented by y=9.8x (where y signifies velocity and x indicates time):
The displacement graph can be described as y=4.9x^2 (with x as time and y as displacement):
These graphs apply exclusively from x=0 to x=1.9, so disregard other sections of the graphs.
The complete question is;
Block 1 sits on the floor with block 2 resting atop it. Block 3, which is stationary on a frictionless table, is attached to block 2 via a string that passes over a pulley depicted in the illustration below. Both the string and pulley have negligible mass.
Once block 1 is taken away without impacting block 2.
Derive an equation for the acceleration of block 3 considering arbitrary values for m3 and m2. Express your answer in terms of m3, m2, and relevant physical constants as needed.
Answer:
a = (m2)g/(m3 + m2)
Explanation:
Examining the attached illustration, by analyzing the free body diagram for block 3 and utilizing Newton's first law of motion, we reach the following formula;
T = (m3)a - - - (eq 1)
where;
T is the tension in the string
a is acceleration
m3 is the mass of block 3
Simultaneously, doing the same for Block 2, the free body diagram yields the equation; (m2)g - T = (m2)a
Rearranging for T results in;
T = (m2)g - (m2)a - - - (eq 2)
where;
g represents acceleration due to gravity
T is the tension in the string
a is acceleration
m2 is the mass of block 2
To deduce the acceleration, we will substitute (m3)a in place of T in eq 2.
Thus;
(m3)a = (m2)g - (m2)a
(m3)a + (m2)a = (m2)g
a(m3 + m2) = (m2)g
a = (m2)g/(m3 + m2)
