Answer:
La magnitud del EMF es 0.00055 volts
Explanation:
El EMF inducido es proporcional al cambio en el flujo magnético según la ley de Faraday:
Como en nuestro caso hay solo un lazo de alambre, entonces N=1 y obtenemos:
Necesitamos expresar el flujo magnético dada la geometría del problema;
donde A es el área de la bobina que permanece constante con el tiempo, y B es el campo magnético que cambia con el tiempo. Por lo tanto, la ecuación para el EMF se convierte en:
Answer:
A) and B) are valid.
Explanation:
When an object remains at rest, it is indicative that no net force acts upon it.
The downward gravitational force from Earth must be counterbalanced by an upward force of equal magnitude in order to maintain rest.
This upward force is provided by the normal force, which adjusts to satisfy Newton’s 2nd Law and is always perpendicular to the surface supporting the object (in this instance, the ground).
At the molecular level, this normal force comes from the ground's bonded molecules acting like tiny springs, compressed by the object’s molecules, providing an upward restorative force.
Thus, statements A) and B) are true.
To find the mass using a weight of 1.4 N:
1.4/9.8 = 0.1428 kg
The momentum is calculated as 0.1428 multiplied by 44.7, which is 6.38 kgm/s.
Answer:T = 0.03 Nm.
Explanation:
d = 1.5 in = 0.04 m
r = d/2 = 0.02 m
P = 56 kips = 56 x 6.89 = 386.11 MPa
σ = 42 ksi = 42 x 6.89 = 289.58 MPa
To find Torque = T =?
Solution:σ = (P x r) / T
Thus, T = (P x r) / σ
Calculating T = (386.11 x 0.02) / 289.58
results in T = 0.03 Nm.
