On a day when the water is flowing relatively gently, water in the Niagara River is moving horizontally at 4.5 m/sm/s before sho

Question

3 months ago

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On a day when the water is flowing relatively gently, water in the Niagara River is moving horizontally at 4.5 m/sm/s before sho

oting over Niagara Falls. After moving over the edge, the water drops 53 mm to the water below.
a. If we ignore air resistance, how much time does it take for the water to go from the top of the falls to the bottom?
b. Express your answer to two significant figures and include the appropriate units.
c. How far does the water move horizontally during this time?
d. Express your answer to two significant figures and include the appropriate units.

Physics

1 answer:

Maru [3.3K] · Answer 1 · 2026-02-23T17:21:04+03:00

Answer:

a.3.29 m/s

b.3.3 m/s

c.14.8 m

d.15 m

Explanation:

We have the following specifics:

Initial Horizontal speed= $v_x=4.5 m/s$

Vertical component of initial speed= $v_y=0$

Vertical distance= $y=-53 m$

a. $s=ut+\frac{1}{2}gt^2$

Applying the formula and considering g as negative results in $g=-9.8m/s^2$

$-53=0-\frac{1}{2}(9.8)t^2$

$53=4.9t^2$

$t^2=\frac{53}{4.9} s$

$t=\sqrt{\frac{53}{4.9}}=3.29m/s$

b.Since the hundredths place exceeds 5, 1 is added to the tenths place, while other digits to the left remain unchanged and the digit to the right is replaced by 0.

$t=3.3 m/s$

c.Horizontal acceleration= $a_x=0$

$x=v_xt=4.5\times 3.29=14.8 m$

d.The digit in the tenths place at 8 surpasses 5, thus adding 1 to the units place, with all other digits on the left side unchanged and the right-side digit altered to 0.

Horizontal distance=15 m