At a football game, an air gun fires T-shirts into the crowd. The gun is fired at an angle of 46 degree from the horizontal with

Question

2 months ago

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At a football game, an air gun fires T-shirts into the crowd. The gun is fired at an angle of 46 degree from the horizontal with

an initial speed of 27 m/s. A fan who is sitting 60 m horizontally from the gun, but high in the stands, catches a T-shirt. A) How long does it take for the T-shirt to reach the fan? B) At what height h is the fan from the ground?

Physics

1 answer:

Keith_Richards [3.2K] · Answer 1 · 2026-03-07T07:42:34+03:00

Response:

a) $t=3.199 seconds$

b) $h = 11.97 m$

Clarification:

As this situation pertains to projectile motion,

a) we know that

$Vcos\theta=\frac{R}{t}$

Where,

V = initial velocity

Θ = angle with respect to the horizontal

R = horizontal distance

t = duration to traverse the distance 'R'

Given values:

V = 27m/s

R = 60m

Θ = 46°

Thus,

the formula transforms to

$27\times cos46^o=\frac{60}{t}$

or

$t=\frac{60}{27\times cos46^o}$

$t=3.199 seconds$

b) The equation for height can be expressed as:

$h = Vsin\theta \times t-\frac{1}{2}\times gt^2\\$

where,

g = acceleration due to gravity = 9.8m/s²

Substituting the values into the above equation results in

$h = 27\times sin46^o\times 3.199-\frac{1}{2}\times 9.8\times 3.199^2\\$

or

$h = 62.124-50.14$

or

$h = 11.97 m$