HNO₃ → H⁺ + NO₃⁻
v₁=35.0 mL
c₁=0.255 mmol/mL
n₁(NO₃⁻)=v₁c₁
Mg(NO₃)₂ → Mg²⁺ + 2NO₃⁻
v₂=45.0 mL
c₂=0.328 mmol/mL
n₂(NO₃⁻)=2c₂v₂
c₃={n₁+n₂}/(v₁+v₂)={c₁v₁ + 2c₂v₂}/(v₁+v₂)
c₃={35.0*0.255+2*0.328*45.0}/(35.0+45.0)≈0.481 mmol/mL
a. 0.481 m
Carbon disulfide (S=C=S) consists of a single carbon atom and two sulfur atoms. Carbon possesses 4 valence electrons, whereas sulfur has 6. In the bonding process, all four valence electrons from carbon participate, while each sulfur atom provides two electrons for bonding. Consequently, a total of 4 + 2(2) = 8 electrons are involved in bonding, while there are 8 electrons (four from each sulfur atom) that remain unbonded.
For 1.000 g of X, the mass of Y is 0.1621 g. The mass ratio of Y = 2.100 g: 0.1621 g equals 1:0.07. For 1.000 g of X, the mass of Y is 0.7391 g, which leads to a mass ratio of Y = 2.100 g: 0.7391 g simplifying to 1:0.35 or 20:7. For 1.000 g of X, the corresponding mass of Y is 0.2579 g, yielding a mass ratio of Y = 2.100 g: 0.2579 g resulting in 1:0.12. For 1.000 g of X, the mass of Y becomes 0.2376 g, giving a mass ratio of Y = 2.100 g: 0.2376 g, simplifying to 1:0.11. Lastly, for 1.000 g of X, the mass of Y is determined to be 0.2733 g, leading to a mass ratio of Y = 2.100 g: 0.2733 g which reduces to 1:0.13. Among the calculated values, option B aligns most closely with the law of multiple proportions.
Sr(s)+Mg²+(aq)→Sr²+(aq)+Mg(s)
Number of electrons transferred, n=2. Equilibrium constant,
K=2.69×10∧12
ΔG=-2.303RT logK
R=gas constant=8.314J/mol-k
T= temperature in K= 25°C=25+273=298K
Calculating gives us ΔG = -70922.3J. However, ΔG = -nFE
n= number of electrons transferred in the reaction =2
F= faraday = 96500C
E=cell potential is what?
∴E = ΔG.nF
=-(-70922.3)/2×96500)
=0.367V.
