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maxonik
5 days ago
11

The next 3 questions will walk you through using the Henderson-Hasselbalch equation for the following question. For each step pr

ovide a numerical answer. A solution is made by combining 300mL of 0.020M trimethyl amine, that is (CH3)3N and a 500mL of a 0.03M solution of it's conjugate acid, that is (CH3)3NH . The Kb for trimethyl amine is 6.3x10-5. The Henderson-Hasselbalch equation uses pKa not Kb, Calculate the pKa....
Chemistry
1 answer:
lions [985]5 days ago
8 0

Response:

The pKa value is 13.0.

Clarification:

pKa + pKb = 14

For trimethylamine, Kb = 6.3 × 10^{-5}

Calculating pKb: pKb = - log (6.3 × 10^{-5})

= 1.0

Thus, pKa = 14 - pKb = 14 - 1.0

pKa = 13.0

Verification: The typical range for pKa in weak acids is from 2 to 13.

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A certain chemical reaction releases 362.kj of heat energy per mole of reactant consumed. Suppose some moles of the reactant are
lions [985]

Answer:

The temperature increase of the calorimeter, which is missing in the problem, is necessary for the calculation.

Explanation:

Since the temperature rise (X) is unspecified, we'll express the calculation in terms of X, and demonstrate with an example value.

1) Calorimeter details:

  • Temperature increase: X °C
  • Heat capacity ratio: 4.87 J / 5.5 °C (given)
  • Energy absorbed by calorimeter at X °C rise:

                (4.87 J / 5.5 °C) × X

2) Reaction data:

  • Heat released: 362 kJ per mole of reactant
  • Number of moles consumed: n
  • Total energy from reaction:

     362 kJ/mol × 1000 J/kJ × n = 362,000 n J

3) Using energy conservation, assuming no heat loss to surroundings, the energy from the reaction equals the energy absorbed by the calorimeter:

  • 362,000 n = (4.87 J / 5.5 °C) × X

  • Solving for n gives:

  • n = [(4.87 / 5.5) × X] / 362,000

     n = 0.000002446 × X

This means for each degree Celsius rise in calorimeter temperature, 0.000002446 moles of reactant were consumed.

Example:

If the calorimeter temperature increases by 100 °C, then:

  • n = 0.000002446 × 100 = 0.0002446 mol

6 0
14 days ago
What is [h3o ] in a solution of 0.25 m ch3co2h and 0.030 m nach3co2?
Anarel [852]

Hello!

To find [H₃O⁺], we will employ the Henderson-Hasselbalch equation, as this involves an acid and its conjugate base:

pH=pKa+log( \frac{[A^{-}] }{[HA]} )

pH=4,76+log( \frac{0,030M}{0,25M} ) \\ \\ pH=3,84

Next, we derive [H₃O⁺] using the definition of pH:

pH=-log[H_3O^{+}]

[H_3O^{+}] = 10^{-pH} =10^{-3,84}=0,00014 M

Hence, the concentration of [H₃O⁺] comes out to be 0.00014 M

Wishing you a good day!

4 0
12 days ago
The density of a cube is 2.0gcm3. If the mass is 128 g, what is the length of each side of the cube?
eduard [944]

Density is calculated as Mass divided by Volume.

Volume can also be expressed as Mass divided by Density.

Volume becomes 2 divided by 128.

This results in Volume equal to 1/64.

Therefore, each side measures 4 cm.

5 0
5 days ago
Read 2 more answers
Charlie is frying an egg in a pan located over a gas burner. He develops a model to determine the energy produced by the flame i
lorasvet [956]

Answer: B.)

Explanation: Heat transfers from the pan to the surrounding environment.

8 0
11 days ago
Which statement is true about molarity and percent by mass?
Anarel [852]

Answer: The correct choice is that they represent different concentration units.

Explanation:

Molarity: Defined as the quantity of solute moles in a liter of solution.

Molarity formula:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution in liters}}

Mass percent: Represents the mass of solute relative to the total mass of the solution.

Mass percent formula:

\text{Mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

This demonstrates that they are distinct units of concentration.

5 0
11 days ago
Read 2 more answers
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