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const2013
2 days ago
13

Calculate the mass of KI in grams required to prepare 5.00 X10^2 mL of a 2.80 M solution

Chemistry
2 answers:
Alekssandra [968]2 days ago
3 0
Volume in liters:

5.00x10² mL / 1000 => 0.5 L

Molar mass of KI => 166.0028 g/mol

Calculating mass of KI = volume x molar mass x molarity

Mass of KI = 0.5 x 166.0028 x 2.80

= 232.40392 g of KI

I hope this is helpful!

Alekssandra [968]2 days ago
3 0

Explanation:

Molarity refers to moles per liter of solution, while the number of moles is defined as mass divided by molar mass.

Consequently,       Molarity =  \frac{mass}{molar mass \times volume of solution}

Given that the molarity is 2.80 M, the volume is 500 mL or 0.5 L, and the molar mass of KI is 166 g/mol.

Thus,     mass = Molarity \times molar mass \times volume of solution}          

                          = 2.80 mol/L \times 166 g/mol \times 0.5 L

                          = 232.4 g

Therefore, the mass of KI required to prepare 5.00 X10^2 mL of a 2.80 M solution is 232.4 g.

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Please review the following responses

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