answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pepsi
2 months ago
5

Use the tabulated values of ΔG∘f to calculate E∘cell for the fuel cell breathalyzer, which employs the reaction below. (ΔG∘f for

HC2H3O2(g)= -374.2 kJ/mol.) CH3CH2OH(g)+O2(g)→HC2H3O2(g)+H2O(g)
Chemistry
1 answer:
castortr0y [3K]2 months ago
7 0
0.97 V The relationship between ΔGºf and Eºcell is given by ΔGºf = -nFEºcell, where ΔGºf is the Gibbs Free energy change of formation at STP in Joules, n represents the number of moles of electrons, F is Faraday's constant (96,500 coulombs), and Eºcell indicates the emf of the cell under standard conditions. The redox reaction is CH3CH2OH(g) + 2H2O ⇒ HC2H3O2(g) + 4 H⁺ +4e⁻; O2 + 4 H⁺ + 4e⁻ ⇒ 2 H2O. Using the formula Eºcell = -ΔGºf /nF = -374.2 x 1000 J/(4x 96500 coulombs) gives 0.97 V.
You might be interested in
Milk, if 2.00 liters has a mass of 2.06 kg. Find the density in g/cm^3
lorasvet [2795]
The density is 1.03 g/cm³. Explanation: The density of a substance is calculated with the formula: 1 kg = 1000 g therefore 2.06 kg = 2060 g. 1 L = 1000 cm³ thus 2 L = 2000 cm³. We now find: Mass = 2060 g Volume = 2000 cm³. Thus, the final answer of density is: 1.03 g/cm³. I hope this information assists you.
5 0
1 month ago
Read 2 more answers
Write the formulas for the following ionic compounds: (a) copper bromide (containing the Cu+ ion), (b) manganese oxide (containi
Anarel [2989]

Answer: The formulas for the ionic compounds are:

a)CuBr

b)Mn_2O_3

c)Hg_2I_2

d)Mg_3(PO_4)_2

Explanation:

Determining the formulas for ionic compounds relies on:

The criss-cross method, wherein the oxidation states of ions are exchanged, forming the subscripts of the respective ions, resulting in a neutral compound.

(a) Copper bromide is formed based on the Cu^+ ion.

Cu^++Br^-\rightarrow CuBr

(b) Manganese oxide originates from the inclusion of the Mn^{3+} ion.

Mn^{3+}+O^{2-}\rightarrow Mn_2O_3

(c)Mercury iodide contains the Hg_2^{2+}

Hg_2^{2+}+I^-\rightarrow Hg_2I_2

(d) Magnesium phosphate includes the PO_4^{3-}

Mg^{2+}+PO_4^{3-}\rightarrow Mg_3(PO_4)_2

4 0
2 months ago
What would be the mass in grams of 1.204 x 1024 molecules of sulfur dioxide
Tems11 [2777]
mass of sulfur = 96 g no of moles of sulfur dioxide in 1.204\times 10^{24} molecules = \frac{1.204\times 10^{24}}{avagadro number }= \frac{1.204\times 10^{24}}{6.023\times 10^{23}} = 2 moles therefore mass of sulfur dioxide = moles × atomic number = 2 × (16 + 32) = 96
6 0
1 month ago
How many grams are in 2.3 x10-4 moles of calcium phosphate ca3(po3)2
Alekssandra [3086]

Answer:

Calcium phosphate has the formula Ca3(PO4)2, which has a molar mass of 310 grams per mole.

<p1 mole="" consists="" of="" grams.="">

For 2.3*10^-4 moles, we calculate 2.3*10^-4 * 310, resulting in 713*10^-4 grams, or 71.3 milligrams.

If the formula is accurate but the compound's name is incorrect, simply replace 310 with 278, yielding 639.4*10^-4 grams, equivalently 63.94 milligrams.

</p1>
6 0
2 months ago
An unknown compound, X is thought to have a carboxyl group with a pKa of 2.0 and another ionizable group with a pKa between 5 an
alisha [2963]

Answer:

7.3

Explanation:

Using the Henderson Hasselbalch equation, one can determine the pH or pOH of a solution via its pKa. Remember, pH = -log[H^{+}], and pKa = -logKa, where Ka denotes the acid's equilibrium constant.

The Henderson Hasselbalch formula:

pH = pKa - log \frac{[HA]}{[A^{-}]}

In this context, acid X possesses two ionic forms: the carboxyl group and an alternative form. Initially, we have 0.1 mol/L of acid in 100 mL, which gives:

n1 = (0.1 mol/L)×(0.1 L) = 0.01 mol

Upon dissociation, it yields 0.005 mol of the carboxyl form and 0.005 mol of the other form with stoichiometry assumed constant.

Introducing NaOH at a concentration of 0.1 mol/L and 75 mL, the moles of OH^- become:

n2 = (0.1 mol/L)×(0.075 L) = 0.0075 mol

Thus, 0.0075 mol of OH^- reacts with 0.005 mol of the carboxyl form, leading to 0.0025 mol of OH^-, which in turn reacts with 0.005 mol of the alternating group, leaving 0.0025 mol of the latter.

The new solution’s volume is 175 mL, but the concentrations of both forms remain unchanged in volume, so we can utilize the moles in the equation.

<pNote, the moles of the acid form remain 0.01 mol as it doesn’t undergo reaction!

Thus, we arrive at:

6.72 = pKa - log \frac{0.01}{0.0025}

6.72 = pKa - log 4

pKa - log 4 = 6.72

pKa = 6.72 + log 4

pKa = 6.72 + 0.6

pKa = 7.3

8 0
3 months ago
Other questions:
  • A sample of H2SO4 contains 2.02 g of hydrogen, 32.07 g of sulfur, and 64.00 g of oxygen. How many grams of sulfur and grams of o
    13·1 answer
  • Leonard adds 5 grams of sugar to 1 liter of water to make one sugar solution. Then he adds 10 grams of sugar to 1 liter of water
    9·1 answer
  • Addition of an excess of lead (II) nitrate to a 50.0mL solution of magnesium chloride caused a formation of 7.35g of lead (II) c
    10·1 answer
  • The reaction between nitrogen dioxide and carbon monoxide is NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) The rate constan
    6·1 answer
  • The final overall chemical equation is Upper Ca upper O (s) plus upper C upper O subscript 2 (g) right arrow upper C a upper C u
    15·1 answer
  • For which applications would you choose a liquid over a gas or solid?
    12·2 answers
  • The symbol for xenon (Xe) would be a part of the noble gas notation for the element antimony. cesium. radium. uranium.
    12·2 answers
  • Identify the following redox reactions by type. Check all that apply. (a) Fe + H2SO4 → FeSO4 + H2 combination decomposition disp
    11·1 answer
  • What is the mass of a solution that has a density of 0.775 g/ml and a volume of 50.0ml?
    8·1 answer
  • A red car and a black car begin to accelerate from rest at the same time. The red car accelerates at a constant rate of 3 meters
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!