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den301095
3 months ago
15

What is the Physics Primer?

Physics
2 answers:
kicyunya [3.2K]3 months ago
7 0

Answer:

A. a collection of mathematical topics that are pertinent to basic physics.

Explanation:

The physics primer is not the same as the comprehensive online mathematics textbooks. Instead, it comprises topics in mathematics that challenge students and are noteworthy.

Therefore, it can be understood as the framework for resolving physics-related problems. Thus, mathematical skills are integral within physics courses, serving as a preparatory tool for success.

In summary, it represents a compilation of mathematical subjects that are relevant to foundational physics.

Ostrovityanka [3.2K]3 months ago
5 0

Answer:

A collection of mathematical subjects pertinent to introductory physics courses.

Explanation:

The Physics Primer includes tutorials, videos, and responses to particular inquiries, aimed at establishing a robust foundation of mathematical principles for beginners in physics. Moreover, Physics Primer enhances students' ability to visualize problems and approach them from various viewpoints. The mathematical concepts developed during the course can greatly benefit students, especially if this course is completed prior to the introductory physics class.

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Suppose you push a hockey puck of mass m across frictionless ice for a time 1.0 s, starting from rest, giving the puck speed v a
Softa [3030]
According to Newton's second law, Force equals the rate of change of momentum over time. Momentum change is equal to Force times time. So, F=ma can be rearranged to a=F/m, a more recognizable formulation of Newton's second law
Using a relevant kinematic equation for mass m: V=u+at; where initial speed u=0; thus, acceleration a=F/m gives V=(F/m)xt, which translates to t=mV/F. For mass 2m, applying the same formula: V=u+at; u=0; a=F/2m indicates V=(F/2m)xt, leading to t=2mV/F (possibly double the initial time)
I might have erred somewhere along the line, but the fundamental concept seems valid... using another kinematic equation for m: s=ut + (1/2)at²; with s=d; and initial speed u=0; a=F/m; t=1; results in d=(1/2)(F/m) = F/2m. Similarly, for 2m: s=ut + (1/2)at²; s=d; u=0; a=F/2m; and t=1 gives d=(1/2)(F/2m)=F/4m (half the distance perhaps???? WHAT???!)
3 0
3 months ago
Read 2 more answers
If the potential difference across the bulb in a certain flashlight is 3.0 V, What is the potential difference across the combin
Yuliya22 [3333]

Answer:

The voltage across the bulb measures 3.0 V,

Explanation:

The bulb's voltage aligns with the voltage of the batteries, as they are the only power source for the bulb. Therefore, the voltage across the batteries is 3.0 V.

3 0
3 months ago
The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles
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The masses of particle A, B, and C are given, with all three particles aligned linearly. The distances between them are noted. The gravitational forces are attractive, compounding when acting in the same direction. The effects on each particle are formulated based on their distances.
3 0
2 months ago
The magnitude of the electrical force acting between a +2.4 × 10–8 C charge and a +1.8 × 10–6 C charge that are separated by 0.0
kicyunya [3294]
To solve this problem, Coulomb's law will be applied as follows:
F = k*q1*q2 / r^2 where:
F indicates the force magnitude between the charges
k is a constant = 9.00 * 10^9 N.m^2/C^2
q1 = <span>+2.4 × 10–8 C
q2 = </span><span>+1.8 × 10–6 C
r represents the distance separating the charges = </span><span>0.008 m

By substituting these values, we derive:
F = (9*10^9)(2.4*10^-8)(1.8*10^-6) / (0.008)^2 = 6.075, which rounds to 6.1 Newtons

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8 0
3 months ago
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True or False: Molecules in a gas resist crowding and get as far apart as possible. Free electrons also resist crowding and get
ValentinkaMS [3465]

Answer:

This assertion is inaccurate.

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In contrast, the separation among electrons is primarily influenced by repulsive forces, not random movement as in gases. Electrons maintain distance as a result of repulsion between similarly charged particles. Therefore, the arrangement of electrons on a charged copper sphere occurs not from a random distribution but rather due to repulsion, establishing a set distance between them.

4 0
2 months ago
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