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Rashid
1 month ago
15

Early investigators (including Thomas Young) measured the thickness of wool fibers using diffraction. One early instrument used

a collimated beam of 560 nm light to produce a diffraction pattern on a screen placed 30 cm from a single wool fiber.
part a: If the fiber's diameter was 18 μm, what was the width of the central maximum on the screen?
Physics
1 answer:
ValentinkaMS [3.4K]1 month ago
8 0

Answer:

w= 1.867\times10^{-2}

Explanation:

Provided:

fiber diameter d= 18 μm

screen distance D= 30 cm

wavelength λ= 560 nm

from this, we can determine the fringe width

w=\frac{2\lambda D}{d}

substituting the values yield

w=\frac{2\times560\times10^{-9}\times0.3}{18\times10^{-6}

w= 1.867\times10^{-2}

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inna [3103]

Let us denote a_1=3 m/s^2 as the highest acceleration of the truck by itself. The force generated by the engine to propel the truck in this scenario is
F= ma_1
where m is the mass of the truck alone.

Upon attaching a bus that has double the mass of the truck, the total mass of the entire system (truck+bus) becomes (m+2m)=3m. In this situation, the force generated by the engine is
F=3m a_2
where a2 represents the new acceleration. 
Since the engine remains unchanged, the force generated stays the same, allowing us to set the force equations equal to each other:
m a_1 = 3 m a_2
and solving for a2 gives us:
a_2 = \frac{m a_1}{3 m}= \frac{a_1}{3}= \frac{3 m/s^2}{3}=1 m/s^2

5 0
1 month ago
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A mouse runs along a baseboard in your house. The mouse's position as a function of time is given by x(t)=pt2+qt, with p = 0.36
ValentinkaMS [3465]

Response:

0.60 m/s

Details:

The average speed between times t = a and t = b can be expressed as:

v_avg = (x(b) − x(a)) / (b − a)

Given the function x(t) = 0.36t² − 1.20t, and considering the interval from 1.0 to 4.0:

v_avg = (x(4.0) − x(1.0)) / (4.0 − 1.0)

v_avg = [(0.36(4.0)² − 1.20(4.0)) − (0.36(1.0)² − 1.20(1.0))] / 3.0

v_avg = [(5.76 − 4.8) − (0.36 − 1.20)] / 3.0

v_avg = [0.96 − (-0.84)] / 3.0

v_avg = 0.60

The average speed calculated is 0.60 m/s.

5 0
1 month ago
An end of a light wire rod is bent into a hoop of radius r. The straight part of the rod has length l; a ball of mass M is attac
ValentinkaMS [3465]

Answer:

arcsin(\frac{R\mu}{(R+l)\sqrt{\mu^2+1}})

Explanation:

By applying the Law of Sines,

sin \theta = \frac{sin \phi R}{ l + R}

Based on Newton's Law,

mg = N\sqrt{\mu^2+1}

And the final equation also derived from Newton's Law,

\mu N = mgsin\phi

Then by consolidating all the equations together,

\mu N = mgsin\phi = N\sqrt{\mu^2+1}sin\phi\\

sin\theta = \frac{\mu R}{ (l + R)\sqrt{\mu^2+1}}

Thus,

\theta = arcsin(\frac{R\mu}{(R+l)\sqrt{\mu^2+1}})

8 0
12 days ago
If you are anchored in a fixed spot, and a set of six waves pass underneath you during a 60 second time interval, what is the wa
Ostrovityanka [3204]

Answer:

Explanation:

Within a duration of 60 seconds, six waves are observed.

With a total of 6 waves,

this equates to 3 wavelengths.

As a result,

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According to the frequency-period relationship,

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5 0
1 month ago
Jack pulls a sled across a level field by exerting a force of 110 n at an angle of 30 with the ground. what are the parallel and
Softa [3030]
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For the component perpendicular to the ground:
y = rsin</span>β
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<span>y = 55</span>
3 0
1 month ago
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