Use Wien’s Law to calculate the peak wavelength of Betelgeuse, based on the temperature found in Question #8. Note: 1 nanometer

Question

6 days ago

14

(nm) = .0000001 centimeters (cm) 208nm 400nm 828nm 1800nm

1 answer:

inna [2.2K] · Answer 1 · 2026-03-20T00:15:12+03:00

The peak wavelength for Betelgeuse is 828 nm

Explanation:

Wien's law describes how the surface temperature relates to a star’s peak wavelength:

$\lambda=\frac{b}{T}$

where

$\lambda$ represents the peak wavelength

T is the surface temperature

$b=2.898\cdot 10^{-3} m\cdot K$ is Wien's constant

For Betelgeuse, the surface temperature is roughly

T = 3500 K

Consequently, its peak wavelength can be determined as:

$\lambda=\frac{2.898\cdot 10^{-3}}{3500}=8.28\cdot 10^{-7} m = 828 nm$

Learn more about wavelength: