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givi
3 months ago
14

Use Wien’s Law to calculate the peak wavelength of Betelgeuse, based on the temperature found in Question #8. Note: 1 nanometer

(nm) = .0000001 centimeters (cm) 208nm 400nm 828nm 1800nm
Physics
1 answer:
inna [3.1K]3 months ago
8 0

The peak wavelength for Betelgeuse is 828 nm

Explanation:

Wien's law describes how the surface temperature relates to a star’s peak wavelength:

\lambda=\frac{b}{T}

where

\lambda represents the peak wavelength

T is the surface temperature

b=2.898\cdot 10^{-3} m\cdot Kis Wien's constant

For Betelgeuse, the surface temperature is roughly

T = 3500 K

Consequently, its peak wavelength can be determined as:

\lambda=\frac{2.898\cdot 10^{-3}}{3500}=8.28\cdot 10^{-7} m = 828 nm

Learn more about wavelength:

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