Use Wien’s Law to calculate the peak wavelength of Betelgeuse, based on the temperature found in Question #8. Note: 1 nanometer

<span>this might be useful
Regarding the field, the two charges placed opposite cancel each other out!
Therefore, E = kQ / d² = k * Q / (d/√2)² = 2*k*Q / d² ◄
given k = 8.99×10^9 N·m²/C²,
E = 1.789×10¹⁰ N·m²/C² * Q / d² </span>

To tackle this issue, it's essential to understand the conversion of pounds to kilograms:
1 lb = 0.45 Kg
By applying a straightforward rule of three
1 lb ---> 0.45 Kg
125 lb ---> x
Solving for x yields:
x = ((125) / (1)) * (0.45) = 56.25 Kg.
 Response
 her mass in kilograms is 56.25 Kg.

Answer:

The equivalent distance in kilometers is 4012 × km.

Explanation:

It's known that 1 millimeter converts to meters. Then, 1 meter converts to kilometers. Therefore, the conversion for 1 millimeter to kilometers can be stated as

1 mm = m

1 m = km

Thus, 1 mm = × km = km.

Given the distance of 4012 mm, the corresponding distance in kilometers will be

4012 mm = 4012 × km.

The distance therefore is 4012 × km.

Respuesta:

11.4 m/s

Explicación:

La fórmula para la aceleración centrípeta es:

donde, a es la aceleración, v la velocidad alrededor de la circunferencia y R el radio del círculo.

En este problema,

a = g = aceleración debida a la gravedad en la cima =

v = ?

R = 13.2 m

Por lo tanto,

v = 11.4 m/s

Thanks for asking your question here. I hope this response provides clarity. Feel free to ask additional questions. The moment resulting from the two forces about point O is 376 lb-ft counterclockwise.