Answer:
ΔL = MmRgt / (2m + M)
Explanation:
The system starts from rest, so the change in angular momentum correlates directly to its final angular momentum.
ΔL = L − L₀
ΔL = Iω − 0
ΔL = ½ MR²ω
To determine the angular velocity ω, begin by drawing a free body diagram for both the pulley and the block.
For the block, two forces act: the weight force mg downward and tension force T upward.
For the pulley, three forces are present: weight force Mg down, a reaction force up, and tension force T downward.
For the sum of forces in the -y direction on the block:
∑F = ma
mg − T = ma
T = mg − ma
For the sum of torques on the pulley:
∑τ = Iα
TR = (½ MR²) (a/R)
T = ½ Ma
Substituting gives:
mg − ma = ½ Ma
2mg − 2ma = Ma
2mg = (2m + M) a
a = 2mg / (2m + M)
The angular acceleration of the pulley is:
αR = 2mg / (2m + M)
α = 2mg / (R (2m + M))
Finally, the angular velocity after time t is:
ω = αt + ω₀
ω = 2mg / (R (2m + M)) t + 0
ω = 2mgt / (R (2m + M))
Substituting into the previous equations gives:
ΔL = ½ MR² × 2mgt / (R (2m + M))
ΔL = MmRgt / (2m + M)
Answer:
the lump descends
Explanation:
The full articulation of the query is
Upon fully submerging a 3 kg lump of material in a certain fluid, the fluid that would have occupied the space now filled by the lump weighs 2 kg. (a) When released, does the lump float up, sink, or remain steady
(a)
= Buoyant force acting upward on the lump
= mass of irregular lump = 3 kg
= mass of fluid displaced = 2 kg
The upward buoyant force on the lump is given by the weight of the displaced fluid, thus
the weight of the irregular lump of material is represented as
Given that the weight of the lump downward exceeds the upward buoyant force, the lump will indeed descend
Greetings!
Using the formula F = Bqv sin theta, we define F as Force, B as magnetic flux density, q as charge, v as velocity, and theta as the angle created by the moving electrons in relation to the magnetic field.
^^^You can compute the force using that equation^^^
In conclusion, your result would MOST LIKELY be "B".
"<span>-3.9 × 10-14 N"
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<span>I trust my response has been beneficial. Thank you for your question. We look forward to assisting with more inquiries. Have a wonderful day ahead!:</span>
Explanation:
Here’s a revised version of the requirements;
Fill in the blanks with the appropriate terms. Picture a force gauge fixed between the rope and the saddle of the chain carousel. If you keep your feet off the ground while the vehicle is not in motion, the dynamometer shows A / B. When the carousel is spinning, you’ll see C / D displayed on the dynamometer.
A. Your weight including the saddle
C. Value of the rope's strength
B. Your weight
D. Value of the centripetal force
T= 24.5 feet per second. That’s the speed it attains just before hitting the ground.
