The last part of the question is asking;
What was the total amount spent by all (99.7%) students on textbooks in a semester?
Response:
almost all (99.7%) of the students spent between $165 and $315 on textbooks in a semester.
Stepwise clarification:
The standard deviation rule informs that for normally distributed data, approximately 99.7% of observations fall within three standard deviations from the mean.
In this case, we have the given mean as 240, and standard deviation as 25
Thus, calculating three standard deviations below the mean: Mean - 3(standard deviation)
equals 240 - (3 × 25)
yielding 240 - 75 = 165
Now, for three standard deviations above the mean: Mean + 3 (standard deviation) = 240 + (3 × 25)
equals 240 + 75 = 315
Therefore, nearly all (99.7%) of the students spent between $165 and $315 on textbooks in a semester.
The diagrams for parts A and C are included here. For part B, we have circle O. We begin by drawing two radii OA and OC, connecting points A and C to create chord AC. The radius intersects chord AC at point B, bisecting AC into equal segments AB and BC. This gives us two triangles, ΔOBA and ΔOBC, where OA equals OC (since they're radii), OB equals OB (by the reflexive property), and AB is equal to BC (as stated in the question). By applying the SSS triangle congruence criterion, we conclude that ΔOBA is congruent to ΔOBC, allowing us to deduce that ∡OBA equals ∡OBC, both measuring 90°. Thus, OB is perpendicular to AC. Moving on to part D, we again work with circle O and draw the two radii OA and OC, joining points A and C to create chord AC. The radius intersects AC at point B, where AB is perpendicular to AC, meaning ∡B equals 90°. We then consider the right triangles ΔOBA and ΔOBC, and given OA equals OC (the radii), and OB equals OB (reflexive property), we conclude through the HL triangle congruence that ΔOBA is congruent to ΔOBC. Consequently, we find BA equal to BC, thus OB bisects AC.
Yes, the initial response is valid because n squared denotes n with an exponent of 2, and adding 3 to it yields the first result. The three outside indicates multiplication, confirming that the original response is indeed accurate.
