Two race cars,car x an y,are at the starting point of a two km track at the same time.car x and car y make one lap every 60 s an

Answer:

Wyjaśnienie krok po kroku:

Załóżmy, że prostokąt ma wierzchołki (x,y,z) w dodatnim oktancie.  Prostokątny pudełko musi być symetryczne względem wszystkich trzech osi.

Wtedy jego boki to

Objętość =

Maksymalizuj objętość przy założeniu

tj.

Użyj mnożników Lagrange'a, mamy

przy maksimum

Dzieląc otrzymujemy

Podobnie

Zatem otrzymujemy

Stąd wymiary to

(2x,2y,2z)

Question:

Which statement is accurate concerning the function’s discontinuities

A) There are gaps at x = 7 and.

B) Asymptotes exist at x = 7 and.

C) Asymptotes exist at x = –7 and.

D) Gaps are present at (–7, 0) and.

Answer:

B) Asymptotes exist at x = 7 and

Step-by-step explanation:

Given:

Goal:

Identify the correct statement

We need to factor the denominator first.

To express x in terms of (3x+4) and (x-7):

3x + 4 =

3x = -4

Divide both sides by 3:

x - 7

x = 7

Next, evaluate the limit when and at (x = 7)

lim f(x) as = ±∞

lim f(x) as (x=7) = ±∞

Since both scenarios result in the denominator approaching zero, they represent asymptotes.

Thus, asymptotes are found at and x=7

Option B is determined to be correct

n equals 277

9 multiplied by 27 plus 2 multiplied by 31 minus 28 gives n

243 plus 62 minus 28 results in n

305 minus 28 equals n

which means 277 is n

Answer:

Part 1) The algebraic expression can be represented as  or

Part 2) The algebraic expression is represented as

Step-by-step explanation:

Part 1) The expression (n-1) raised by 110%

Recognizing that

110%=110/100=1.10

thus,

The algebraic representation of (n-1) increased by 110% translates to 1.10 multiplied by (n-1).

Expanded

Part 2) The expression n^(-1) raised by 110%

110%=110/100=1.10

therefore, the representation of n^(-1) increased by 110% becomes 1.10 multiplied by n^(-1).

Remember that

thus,