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brilliants
5 days ago
6

There are 15 technicians and 11 chemists working in a research laboratory. In how many ways could they form a 5-member safety co

mmittee if the committee a) may be chosen in any way? b) must have exactly one technician? c) must have exactly one chemist? d) must have exactly two chemists? e) may be all technicians or all chemists?
Chemistry
1 answer:
Tems11 [854]5 days ago
5 0

a)

26C5 -> 26 ways to select 5 items

b)

15C1 × 11C4

c)

11C1 × 15C4

d)

11C2 × 15C2

e)

11C4

or

15C4

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The graph shows the distribution of energy in the particles of two gas samples at different temperatures, T1 and T2. A, B, and C
lions [1003]

Answer:

  • The average velocity of gas molecules at T₂ is less than the average velocity of gas molecules at T₁.

Explanation:

Particles A and C appear aligned vertically, suggesting they share the same kinetic energy. Given that both are positioned to the left of particle B, it indicates that A and C possess lesser kinetic energy than B.

The likelihood of a particle engaging in a reaction is directly proportional to its kinetic energy, meaning that particle B is more prone to react compared to A and C. Thus, the first statement is incorrect.

The graph resembles a bell curve, demonstrating a mixture of many molecules with low and high kinetic energy. Therefore, one cannot conclude that most particles in both gases have high velocities. As a result, the second statement is also incorrect.

Examining the higher kinetic energy values (to the right of the curve), the line for T₁ exceeds that for T₂, indicating that more molecules possess high kinetic energy at T₁ compared to T₂.

Conversely, for lower kinetic energy values (to the left of the curve), T₂'s line is above T₁'s, which implies that at T₂ there are more molecules with low kinetic energy than at T₁.

Thus, the observations from the previous two paragraphs suggest that the average kinetic energy of gas particles at T₂ is lower than the average kinetic energy of particles at T₁.

Since average speed is proportional to the square root of temperature, the relationship that applies to average kinetic energy equally pertains to average speed, leading us to conclude that the last statement holds true: "The average speed of gas particles at T₂ is lower than at T₁.".

Additionally, given that there are more gas molecules at T₁ with higher kinetic energy compared to those at T₂, it indicates that gas particles at T₁ are more likely to react than those at T₂, marking the third statement as incorrect.

7 0
8 days ago
A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal
Tems11 [854]

Answer:

A balloon will hold a gas volume of 45.0 L at a pressure of 1.35 atm and a temperature of 253 K.

Explanation:

Applying the Ideal Gas Law for the same gas amount, we have:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Parameters are given as follows:

V₁ = 25.0 L

V₂ =?

P₁ = 2575 mm Hg

To convert pressure to atmospheres: P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using the earlier formula, we derive:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}

\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}

By solving for V₂, we find:

V₂ = 45.0 L

A balloon will hold a gas volume of 45.0 L at a pressure of 1.35 atm and a temperature of 253 K.

4 0
7 days ago
Combustion analysis of an unknown compound containing only carbon and hydrogen produced 0.2845 g of co2 and 0.1451 g of h2o. wha
VMariaS [1037]
CxHy + (x+0.25)O₂ → xCO₂ + 0.5yH₂O

m(CO₂)/{xM(CO₂)}=m(H₂O)/{0.5yM(H₂O)}

0.2845/{44.01x}=0.1451/{9.01y}

x/y=0.4=2:5

The empirical formula is C₂H₅.
7 0
22 hours ago
Now that Snape and Dumbledore has taught you the finer points of hydration calculations they have a slightly more challenging pr
eduard [944]

Answer:

The integer value of x in the hydrate is 10.

Explanation:

Molarity=\frac{Moles}{Volume(L)}

Molar concentration of the solution = 0.0366 M

Volume of the solution = 5.00 L

Moles of hydrated sodium carbonate = n

0.0366 M=\frac{n}{5.00 L}

n=0.0366 M\times 5 mol=0.183 mol

Weight of hydrated sodium carbonate = n = 52.2 g

Molar mass of hydrated sodium carbonate = 106 g/mol + x * 18 g/mol

n=\frac{\text{mass of Compound}}{\text{molar mass of compound}}

0.183 mol=\frac{52.2 g}{106 g/mol+x\times 18 g/mol}

106 g/mol+x\times 18 g/mol=\frac{52.2 g}{0.183 mol}

By solving for x, we arrive at:

x = 9.95, approximating to 10

The integer x in the hydrate equals 10.

6 0
17 hours ago
A tritium nucleus is formed by combining two neutrons and a proton. the mass of this nucleus is 9.106 × 10–3 universal mass unit
lions [1003]
E = mc²

where E = energy produced

m = mass of the nucleus

C = speed of light

m = 9.106 x 10⁻³ x 1.67 x 10⁻²⁷ kg

C = 3 x 10⁸ m/s, thus C² = 9 x 10¹⁶

E = 1.37 x 10⁻¹² J

7 0
5 days ago
Read 2 more answers
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