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ziro4ka
1 month ago
9

41. A 13.0% solution of K2CO3 by mass has a density of 1.09 g/cm3. Calculate the molality of the solution.

Chemistry
1 answer:
lions [2.9K]1 month ago
5 0

Answer:

The molality of the solution is 1.08 m.

Explanation:

First, determine the mass of the solvent.

A 13% solution by mass indicates that 13 grams are found in every 100 grams of solution.

Thus, solution mass = solute mass + solvent mass

100 g = 13 g + solvent mass

Therefore, solvent mass = 100 g - 13 g → 87 g

Next, we calculate the moles of solute (mass / molar mass):

13 g / 138.2 g/mol = 0.094 moles

Finally, to find the molality, which is the moles of solute per 1 kg of solvent (mol/kg), we convert the solvent mass to kg:

87 g. 1 kg / 1000 g = 0.087 kg

Then, molality → 0.094 mol / 0.087 kg = 1.08 m

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What is the definition of a reflux? What happens to the solvent during a reflux experiment? What are three characteristics of a
alisha [2963]

Response:

a. The return of the process fluid after it has been cooled, condensed, or heated in a distillation column or packing.

b. should remain stable at elevated temperatures

   should not generate additional by-products

   should be chemically inert

c. expressed as a range

d. determined by conducting a series of measurements

e. impurities cause substances to melt at lower temperatures.

Explanation:

a. In a reflux system, the condensate is returned to the initial flask or boiler. This keeps the process fluid at a constant temperature without needing more fuel while increasing the molar fraction of the distillate (which enhances product purity).

b. A solvent needs to be stable and should not participate in side reactions that produce unwanted by-products, ideally remaining inert at elevated temperatures.

c. It is advisable to report melting points as a range since various factors influence the melting point in experimental setups.

d. Melting points can be ascertained through a series of graphical measurements.

e. Impurities reduce the melting point of substances.

4 0
1 month ago
Two different ionic compounds each contain only copper and chlorine. Both compounds are powders, one white and one brown. An ele
alisha [2963]

Answer:

B.

Explanation:

Elemental analysis reveals the precise percentage make-up of each component in the compound sample. Here, we have two distinct compounds, both containing copper and oxygen. However, the specific amounts of copper and oxygen in these compounds remain unknown.

An elemental composition will clarify this aspect and aid in determining the chemical formula for each compound, since the percentage of each element is now understood.

5 0
1 month ago
Identify the limiting reactant when 1.22 g of O2 reacts with 1.05 g H2 to produce water.
lions [2927]
The chemical reaction involving oxygen, O2, and hydrogen, H2, yielding water can be represented as,

            2H2 + O2 --> 2H2O

The masses of the reactants can be calculated as follows:[

          2H2 = 4(1.01 g) = 4.04 g
          O2 = 2(16 g) = 32 g

Considering we have 1.22 grams of oxygen, let's find out how much hydrogen is necessary.
        (1.22 g O2)(4.04 g H2 / 32 g O2) = 0.154 g of O2

Since we have 1.05 grams of O2, this makes 1.22 grams of oxygen the limiting reactant.


Answer: 1.22 g of oxygen
4 0
17 days ago
Consider isotopes ions protons and electrons. how many of these did dalton not discuss in his atomic theory?
KiRa [2933]

The reply is: He did not mention any of these topics.

Explanation: Dalton outlined certain postulates for his atomic theory, which are:

1) Matter consists of indivisible atoms.

2) Atoms from different elements combine in fixed proportions to form compounds.

3) The atomic characteristics of a specific element are uniform, including mass. This means all atoms of a given element share the same mass, whereas atoms from different elements exhibit different masses.

4) During a chemical reaction, atoms are not created or destroyed.

5) Atoms of an element are uniform in mass, size, and all other chemical and physical properties.

From these postulates, it is evident that he focused solely on atoms, neglecting subatomic particles or isotopes.

8 0
21 day ago
Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and
Alekssandra [3086]

Answer:

a. The oxidizing agent is: BH_4^-

b. The reducing agent is: ClO_3^-

Explanation:

Redox reaction, or oxidation-reduction reaction: It refers to a reaction where oxidation and reduction occur at the same time.

Oxidation reaction: It defines a reaction where a substance loses electrons, resulting in an increase in the oxidation state of that element. In essence, oxidation denotes the loss of electrons.

Reduction reaction: This describes a reaction where a substance acquires electrons, with the oxidation state of the element decreasing. Thus, reduction is characterized by the gain of electrons.

Reducing agent: This is the agent that facilitates the reduction of another substance while itself undergoing oxidation. Hence, it partakes in the oxidation reaction.

Oxidizing agent: This agent assists another substance in oxidation while experiencing reduction itself, participating in the reduction reaction.

The provided chemical reaction is,

BH_4^-(aq)+ClO_3^-(aq)\rightarrow H_2BO_3^-(aq)+Cl^-(aq)

Half-reactions for oxidation and reduction are as follows:

Oxidation: BH_4^-\rightarrow H_2BO_3^-

Reduction: ClO_3^-\rightarrow Cl^-

Next, balance the oxygen atoms on each side.

Oxidation: BH_4^-\rightarrow H_2BO_3^-+3H_2O

Reduction: ClO_3^-+3H_2O\rightarrow Cl^-

Next, balance hydrogen atoms on both sides.

Oxidation: BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O

Reduction: ClO_3^-+3H_2O\rightarrow Cl^-+6OH^-

Then balance the charges.

Oxidation: BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O+4e^-

Reduction: ClO_3^-+3H_2O+6e^-\rightarrow Cl^-+6OH^-

To balance the electrons, multiply the oxidation reaction by 6 and the reduction reaction by 4, and then sum both equations to acquire the balanced redox reaction.

Oxidation: 6BH_4^-+24OH^-\rightarrow 6H_2BO_3^-+18H_2O+24e^-

Reduction: 4ClO_3^-+12H_2O+24e^-\rightarrow 4Cl^-+24OH^-

The balanced chemical reaction in an acidic environment is,

6BH_4^-+4ClO_3^-\rightarrow 6H_2BO_3^-+6H_2O+4Cl^-

3BH_4^-+2ClO_3^-\rightarrow 3H_2BO_3^-+3H_2O+2Cl^-

In the redox reaction, ClO_3^- functions as the oxidizing agent and BH_4^- serves as the reducing agent.

7 0
1 month ago
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