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elena-14-01-66
2 months ago
6

The density of a 50% solution of naoh is 1.525 g/ml. what volume of a solution that is 50% by weight naoh is required to make 0.

4 liter of 0.1m naoh solution?
Chemistry
1 answer:
eduard [2.7K]2 months ago
3 0
We assume that the stated 50% is measured by volume. Molarity defines the concentration in terms of moles of solute per volume of solution.

      To find the moles of NaOH, use: (0.1 moles / L)(0.4 L)
                      n = 0.04 moles of NaOH

Assuming we start with 1 mL of 50% NaOH solution, 
  
                        (1 mL solution)(1.525 g/mL)(0.50) = 0.7625 g
Then, the number of moles calculates as follows,[
                  0.7625 g NaOH x (1 mol / 40 g) = 0.01906 moles of NaOH

                The volume of solution required can be determined by:(0.04 moles of NaOH)(1 mL solution / 0.01906 moles of NaOH)
                 
                 Thus, the needed volume comes out to be 2.09 mL

Answer: 2.09 mL
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Answer: The cell potential for the given reaction stands at 0.50 V

Explanation:

The provided cell reaction is:

Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)

The half-reactions are:

Anode oxidation half reaction:  Zn\rightarrow Zn^{2+}+2e^-

Cathode reduction half reaction:  Pb^{2+}+2e^-\rightarrow Pb

Initially, we need to find the cell potential for this reaction.

Utilizing the Nernst equation:

E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}

where,

F = Faraday's constant = 96500 C

R = gas constant = 8.314 J/mol·K

T = room temperature = 25^oC=273+25=298K

n = electrons exchanged in oxidation-reduction = 2

E^o_{cell} = standard electrode potential for the cell = +0.63 V

E_{cell} = cell potential for the reaction =?

[Zn^{2+}] = concentration of Zn²⁺ = 3.5 M

[Pb^{2+}] = 2.0\times 10^{-4}M

Now substituting all known values into the equation, we arrive at:

E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}

E_{cell}=0.50V

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1 month ago
What volume of 0.550 M KBr solution can you make from 100.0 mL of 2.50 M KBr?
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M1V1 = M2V2
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From 100.0 mL of 2.50 M KBr, you can prepare 455 mL of 0.550 M solution.
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A. 1.01 is the accurate result

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In a similar way, rubbing a balloon against your hair generates opposite static charges on both your hair and the balloon. As you gently pull the balloon away from your head, the attraction between these opposite charges can be observed, causing your hair to rise.

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