Answer:
qt's length = 16
Step-by-step explanation:
The problem states that qrs is a right triangle,
where qr = 20
sr =?
qs = 25
qt =?
1)
Calculate sr
hypotenuse² = base² + height²
sq² = sr² + rq²
25² - 20² = sr²
sr = √(25² - 20²)
sr = 15
2)
When altitude rt is dropped to hypotenuse qs, it creates
two right triangles: rtq and rts.
Δrtq
height = rt
base= tq = 25 - x
hypotenuse = qt = 20
Δrts
height = rt
base= ts = x
hypotenuse = sr = 15
Both triangles share the same height, which is rt
Using the Pythagorean theorem:
Δ rtq Δ rts
hypotenuse² - base² = height²
20² - (25 - x)² = 15² - x²
400 - (625 + x² - 50x) = 225 - x²
400 - 625 - x² + 50x = 225 - x²
-225 - x² + 50x - 225 + x² = 0
-450 + 50 x = 0
50x = 450
x = 450/50
x = 9
Base of Δ rtq = tq = 25 - x
tq = 25 - 9
tq = 16
x:200
x/200 =.2121212121...
200(x/200) = 200(.2121212121...)
x = 42.4242...
The expectation is that a player would achieve 42 hits over 200 at-bats.
Let x represent the number of apples and y the number of oranges.
Starting with the first scenario, since each apple is priced at $0.24 and each orange at $0.80, we have:
total spent on apples = 0.24x and total spent on oranges = 0.8y
Given that the total expenditure is $12, the first equation is:
0.24x + 0.8y = 12
For the second scenario, the total number of pieces of fruit purchased is 20, thus the second equation is:
x + y = 20
By graphing these equations, one can identify a potential combination at the intersection of the two lines.
Answer: Adiya's approach is incorrect. To construct a perfect square trinomial, one must isolate the constant on one side of the equation. The coefficient of the term with an exponent of 1 regarding the variable is essential to calculate the constant in the perfect square trinomial. The first step for Adiya should be to reposition the 20x term to the same side of the equation as x2. Then, she should divide 20 by 2, square that result, and add 100 to both sides.
Answer:
The graph's domain encompasses all real numbers.
At
, the graph crosses the y-axis.
The x-axis is intersected at
.
Step-by-step explanation:
Given: The graph is
.
The function's domain refers to the collection of input values where the function is defined and real.
This indicates that the graph has a domain of
.
To determine the y-intercept: Insert
into
.
![\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Dy%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B2%20%5C%5C%26%3D%5Csqrt%5B3%5D%7B0-1%7D%2B2%20%5C%5C%26%3D-1%2B2%20%5C%5C%26%3D1%5Cend%7Baligned%7D)
Therefore, the y-intercept is
.
To determine the x-intercept: Insert
into
.
![\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Dy%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B2%20%5C%5C0%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B2%20%5C%5C-2%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%20%5C%5C%28-2%29%5E%7B3%7D%20%26%3D%28%5Csqrt%5B3%5D%7Bx-1%7D%29%5E%7B3%7D%20%5C%5C-8%20%26%3Dx-1%20%5C%5C-7%20%26%3Dx%5Cend%7Baligned%7D)
Thus, the x-intercept is
.