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3 months ago

Traveling at 65 mph how many feet can you travel in 22 minutes?

2 answers:

6 0

Treat 65 mph as a constant velocity for the purpose of this calculation. By dividing 65 by 60 you find how many miles are covered each minute. That equals 1.083333 miles per minute. Which converts to about 5720 feet each minute. (This comes from multiplying 1.083333 by 5280, the number of feet in a mile). Multiplying 5720 by 22 minutes yields 125,840 feet.

Hope this is helpful!

babunello [11.8K]3 months ago

5 0

The initial step is to convert the provided speed into the appropriate units.

To accomplish that, we employ these unit conversions:

$1 mile = 5280 feet\\1 hour = 60 minutes$

Next, we perform the unit transformation.

$(65)(\frac{miles}{hours}) * (5280)(\frac{feet}{miles}) * (\frac{1}{60})\frac{hours}{min} = 5720 \frac{feet}{min}$

According to the definition, we set up:

$d = v * t$

Where the symbols denote:

d: traveled distance

v: speed

t: time

Plugging in t = 22 minutes yields:

$d = (5720) * (22)\\d = 125840 feet$

Result:

The distance covered in 22 minutes is:

$d = 125840 feet$

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An in-ground pond has the shape of a rectangular prism. The pond has a depth of 24 inches and a volume of 72,000 cubic inches. T

babunello [11817]

Let
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2 months ago

Find the coefficient of x2 in (3x2 – 5) (4 + 4x2), expand using algebraic expressions and answer

babunello [11817]

Answer:

- 8

Step-by-step explanation:

Given the expression

(3x² - 5)(4 + 4x²)

Each term from the second factor is multiplied by every term in the first factor, meaning

3x²(4 + 4x²) - 5(4 + 4x²) ← distribute both parentheses

= 12x² + 12 $x^{4}$ - 20 - 20x² ← combine like terms

= 12 $x^{4}$ - 8x² - 20

The coefficient for the x² term is - 8

7 0

3 months ago

Which function has a simplified base of 4RootIndex 3 StartRoot 4 EndRoot? f(x) = 2(RootIndex 3 StartRoot 16 EndRoot) Superscript

tester [12383]

Response:

$f(x)=4\sqrt[3]{16}^{2x}$

Detailed explanation:

You're likely in search of a function with a base that can be simplified to...

$4\sqrt[3]{4}\approx 6.3496$

The functions you seem to be considering appear to be...

$f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x$

It looks like the third option is the one that fits your requirements.

9 0

2 months ago

Read 2 more answers

Jun and deron are applying for summer jobs at a local restaurant. after interviewing them, the restaurant owner says, "the proba

tester [12383]

<span>As the restaurant owner, The likelihood of hiring Jun is 0.7 => p(J) The likelihood of hiring Deron stands at 0.4 => p(D) The chance of hiring at least one of them is 0.9 => p(J or D) We can formulate the probability equation: p(J or D) = p(J) + p(D) - p(J and D) => 0.9 = 0.7 + 0.4 - p(J and D) p(J and D) = 1.1 - 0.9 = 0.2 Thus, the probability that both Jun and Deron are hired is 0.2.</span>

6 0

2 months ago