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fiasKO
3 months ago
9

Theresa is swinging a 4.0 kg ball on a 1.2 m long rope with a tangential speed of 1.8 m/s. What is the centripetal force exerted

on the rope? Round to the tenths place.
Physics
2 answers:
Keith_Richards [3.2K]3 months ago
8 0
Rounding the number gives us a result of 10.8N.
ValentinkaMS [3.4K]3 months ago
5 0

In this scenario, the centripetal force is expressed as:

F = m * (\frac{v^2}{r})

Where,

m: object mass

v: speed along a tangent

r: radius of the rope

By substituting the values into the equation, we find:

F = (4.0) * (\frac{1.8^2}{1.2})

Next, we perform the necessary calculations:

F = 10.8 N

Result:

The force acting on the rope is:

F = 10.8 N

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a) Average velocity: 2.8 m/s

b) Average velocity: 5.2 m/s

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Explanation:

a)

The car's position over time t can be described by

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where

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\beta = 0.05 m/s^3

To find the average velocity, we divide the displacement by the elapsed time:

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At time t = 0, the position is:

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At time t = 2.00 s, the position is:

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This leads us to the displacement of

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The duration for this interval is

\Delta t = 2.0 s - 0 s = 2.0 s

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b)

At time t = 0, the position is:

x(0)=\alpha \cdot 0^2 - \beta \cdot 0^3 = 0

At time t = 4.00 s, the position is:

x(4)=\alpha \cdot 4^2 - \beta \cdot 4^3=20.8 m

Thus, the displacement is

\Delta x = x(4)-x(0)=20.8-0=20.8 m

The time interval is

\Delta t = 4.0 - 0 = 4.0 s

This yields an average velocity of

v=\frac{20.8}{4.0}=5.2 m/s

c)

The position at t = 2 s is:

x(2)=\alpha \cdot 2^2 - \beta \cdot 2^3=5.6 m

And at t = 4 s it is:

x(4)=\alpha \cdot 4^2 - \beta \cdot 4^3=20.8 m

This gives us a displacement of

\Delta x = 20.8 - 5.6 = 15.2 m

While the time interval is

\Delta t = 4.0 - 2.0 = 2.0 s

So the resulting average velocity is

v=\frac{15.2}{2.0}=7.6 m/s

Find out more about average velocity:

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A book rests on the shelf of a bookcase. The reaction force to the force of gravity acting on the book is 1. The force of the sh
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Answer:

1. The force applied by the shelf supporting the book.

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1 - The weight of the book acting downward

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