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fiasKO
1 month ago
9

Theresa is swinging a 4.0 kg ball on a 1.2 m long rope with a tangential speed of 1.8 m/s. What is the centripetal force exerted

on the rope? Round to the tenths place.
Physics
2 answers:
Keith_Richards [3.2K]1 month ago
8 0
Rounding the number gives us a result of 10.8N.
ValentinkaMS [3.4K]1 month ago
5 0

In this scenario, the centripetal force is expressed as:

F = m * (\frac{v^2}{r})

Where,

m: object mass

v: speed along a tangent

r: radius of the rope

By substituting the values into the equation, we find:

F = (4.0) * (\frac{1.8^2}{1.2})

Next, we perform the necessary calculations:

F = 10.8 N

Result:

The force acting on the rope is:

F = 10.8 N

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1 month ago
the flow energy of 124 L/min of a fluid passing a boundary to a system is 108.5 kJ/min. Determine the pressure at this point
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Answer:

The pressure measured at this moment is 0.875 mPa

Explanation:

Given that,

Flow energy = 124 L/min

Boundary to system P= 108.5 kJ/min

P=1.81\ kW

We are tasked with finding the pressure here

Applying the pressure formula

P=F\times v

P=A_{1}P_{1}\times v_{1}

Here, A_{1}v_{1}=Q_{1}

Where, v refers to velocity

Insert the values into the equation

1.81 =P_{1}\times0.124\times\dfrac{1}{60}

P_{1}=\dfrac{1.81\times60}{0.124}

P_{1}=875.80\ kPa

P_{1}=0.875\ mPa

Therefore, the pressure at this moment is 0.875 mPa

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Read 2 more answers
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