Answer:
v = 54.2 m/s
Explanation:
We can utilize conservation of energy to solve this issue.
Initial condition Higher
Em₀ = U = m g h
Final condition. Lower
= K = ½ m v²
Em₀ = Em_{f}
m g h = ½ m v²
v² = 2gh
v = √ (2gh)
Now let's perform the calculation
v = √ (2 * 9.8 * 150)
v = 54.2 m/s
Response:
The acceleration of car 2 is four times that of car 1.
Rationale:
Centripetal acceleration occurs when an object travels in a circular route. It can be expressed as:

In this scenario, two race cars are moving at consistent speeds around a circular course. Both automobiles are located at an equal distance from the center, but car 2 is operating at twice the speed of car 1.
Thus,

1 and 2 represent the first and second cars, respectively.

Consequently,

Therefore, car 2's acceleration is four times that of car 1.
The equation for simple harmonic motion (SHM) is as follows.
The work performed to elevate the box equals 515.03 J.
Answer:
the temperature on the left side is 1.48 times greater than that on the right
Explanation:
GIVEN DATA:

T1 = 525 K
T2 = 275 K
It is known that


n and v are constant on both sides. Therefore we have

..............1
let the final pressure be P and the temperature 

..................2
similarly
.............3
divide equation (2) by equation (3)
![\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7B11%7D%5E%7B-2%2F3%7D%20%5Cfrac%7B21%7D%7B11%7D%5E%7B5%2F3%7D%20%3D%20%5B%5Cfrac%7BT_1%20%7Bf%7D%7D%7BT_2%20%7Bf%7D%7D%5D%5E%7B5%2F3%7D)

thus, the left side temperature equals 1.48 times the right side temperature