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postnew
3 months ago
14

Two racecars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the

track, but car 2 is driving twice as fast as car 1. The acceleration of car 2 is ___________ the acceleration of car 1. Two racecars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the track, but car 2 is driving twice as fast as car 1. The acceleration of car 2 is ___________ the acceleration of car 1. twice half of equal to four times a quarter of
Physics
1 answer:
Yuliya22 [3.3K]3 months ago
4 0

Response:

The acceleration of car 2 is four times that of car 1.

Rationale:

Centripetal acceleration occurs when an object travels in a circular route. It can be expressed as:

a=\dfrac{v^2}{r}

In this scenario, two race cars are moving at consistent speeds around a circular course. Both automobiles are located at an equal distance from the center, but car 2 is operating at twice the speed of car 1.

Thus,

\dfrac{a_1}{a_2}=\dfrac{v_1^2}{v_2^2}

1 and 2 represent the first and second cars, respectively.

v_2=2v_1

Consequently,

\dfrac{a_1}{a_2}=\dfrac{v_1^2}{(2v_1)^2}\\\\\dfrac{a_1}{a_2}=\dfrac{v_1^2}{4v_1^2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{4}\\\\a_2=4\times a_1

Therefore, car 2's acceleration is four times that of car 1.

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The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 100 volt potential difference is sudde
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Explanation:

Data provided:

Area A = 10 cm×2 cm = 20×10⁻⁴ m²

Separation distance d between the plates = 1 mm = 1×10⁻³ m

Battery voltage, or emf = 100 V

Resistance = 1025 ohm

Solution:

In an RC circuit, the voltage across the plates varies with time t. At the outset, the voltage matches that of the battery, V₀ = emf = 100V. However, after a certain time t, both the resistance and capacitance alter this, leading to a final voltage V expressed as

V = V_{0}(1-e^{\frac{-t}{RC} } )\\\frac{V}{V_{0} } = 1-e(^{\frac{-t}{RC} }) \\e^{\frac{-t}{RC} } = 1- \frac{V}{V_{0} }

Applying the natural logarithm to both sides,

e^{\frac{-t}{RC} } = 1- \frac{V}{V_{0} } \\\frac{-t}{RC} = ln(1-\frac{V}{V_{0} } )\\t = -RCln(1 - \frac{V}{V_{0} })

t = -RC ln (1-\frac{V}{V_{0} })        (1)

Next, we can determine the capacitance using the plates' area.

C = ε₀A/d

  = \frac{(8.85*10^{-12))} (20*10^{-4}) }{1*10^{-3} }

  = 18×10⁻¹²F

We can now find the time it takes for the voltage to drop from 100 to 55 V by substituting C, V₀, V, and R values into equation (1)

t = -RC ln (1-\frac{V}{V_{0} })

 = -(1025Ω)(18×10⁻¹² F) ln( 1 - 55/100)

 = 15×10⁻⁹s

= 15 ns

5 0
2 months ago
Using evidence from the article, defend the concept that Earth’s magnetic poles have swapped places over time.
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Answer: Research has revealed signs of the Earth's magnetic field flipping in ocean floor rocks, especially at tectonic plate boundaries. These rocks exhibit alternating polarity because of the magnetization that happened as they solidified. Through radio metric dating, scientists suggest these reversals take place roughly every few hundred thousand years.

Explanation:

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2 months ago
Determine whether each substance will sink or float in corn syrup, which has a density of 1.36 g/cm3. Write “sink” or “float” in
Sav [3153]

Explanation:

  • A substance will float if it has a lower density than the liquid it is placed in.
  • A substance will sink if its density exceeds that of the liquid.

Density of corn syrup = 1.36 g/cm^3

1) Density of gasoline = 0.748 g/cm^3

Gasoline's density is less than that of corn syrup, indicating it will float in corn syrup.

2) Density of water = 1 g/cm^3

Water's density is also less than that of corn syrup, meaning it will float in corn syrup.

3) Density of honey = 1.45 g/cm^3

Honey's density exceeds that of corn syrup, so it will sink in corn syrup.

4) Density of titanium = 4.506 g/cm^3

The density of titanium is greater than that of corn syrup, hence it will sink in corn syrup.

3 0
3 months ago
Read 2 more answers
A child on a 2.4 kg scooter at rest throws a 2.2 kg ball. The ball is given a speed of 3.1 m/s and the child and scooter move in
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Answer:

The mass of the child is 14.133 kg

Explanation:

According to the principle of linear momentum conservation, we get;

(m₁ + m₂) × v₁ + m₃ × v₂ = (m₁ + m₂) × v₃ - m₃ × v₄

The negative sign signifies that their velocities were directed oppositely

Considering both the child and the ball are initially at rest, we have;

v₁ = 0 m/s and v₂= 0 m/s

Thus;

0 = m₁ × v₃ - m₂ × v₄

(m₁ + m₂) × v₃ = m₃ × v₄

Where:

m₁ = Mass of the child

m₂ = Mass of the scooter = 2.4 kg

v₃ = Final velocity of the child and scooter = 0.45 m/s

m₃ = Mass of the ball = 2.4 kg

v₄ = Final velocity of the ball = 3.1 m/s

Substituting the known values gives us;

(m₁ + 2.4) × 0.45 = 2.4 × 3.1

(m₁ + 2.4) = 16.533

This implies m₁ + 2.4 = 16.533

Thus, m₁ = 16.533 - 2.4 = 14.133 kg

The mass of the child equals 14.133 kg.

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2 months ago
Consider a perfectly insulated cup (no
ValentinkaMS [3465]

Answer:

When ice is subjected to heat, it melts; however, the temperature remains constant at 0◦ C.

Explanation:

Solution

The heat supplied by the heater is solely utilized for the melting of the ice, thus maintaining the temperature at 0◦ C.

Once all the ice has liquefied, the temperature of the resulting water will start to rise over time.

Note: please see the attached document with solutions featuring diagrams related to this explanation

7 0
4 months ago
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