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BartSMP
1 month ago
5

A gold atom has a radius of 145 pm. If you could string gold atoms like beads on a thread, how many atoms would you need to have

a necklace 36 cm long?
Chemistry
1 answer:
VMariaS [2.7K]1 month ago
8 0
Initially we need to perform the conversion:145 pm = 145 * 10^(-12) m; 36 cm = 360 mm = 360 * 10^(-3) m. Then, we can calculate: 360 * 10^(-3) m / 145 * 10^(-12) m = 360 * 10^(-3) * 10^(12) / 145 = 2.482758621 * 10^(9) or:2,482,758,621 atoms.

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Substituting in the values:

V=\frac{8.291x10^{-6}*0.082*299 }{1} =2.033x10^{-4} L=0.2033mL

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<pif the="" quantities="" of="" reactants="" and="" hcl="" are="" diminished="" by="" half="" it="" results="" in:="">

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Consequently, it is clear that the total of H_{2}O produced will be halved if the quantities of the reactants are halved.

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