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18 days ago

An alkene with the molecular formula C8H16 undergoes ozonolysis to yield a mixture of (CH3)2C=O and (CH3)3CCHO. The alkene is:

Chemistry

1 answer:

eduard [2.5K]18 days ago

8 0

The ozonolysis of 2,4,4-trimethyl-2-pentene produces a combination of $(CH_{3})_{2}C=O$ and $(CH_{3})_{3}CHO$

Explanation: In ozonolysis (where a reducing agent like Zn is involved during hydrolysis), a pi bond cleaves to generate ketones or aldehydes.

Ketones arise from the double bond's disubstituted side, whereas aldehydes come from the monosubstituted side of the same bond.

Notably, ozonolysis comprises two steps: (1) the formation of an ozonide, followed by (2) the hydrolysis of the ozonide.

Hydrolysis can transpire with or without a reducing agent. When it occurs without a reducing agent, carboxylic acid, carbon dioxide, or ketones can be produced.

In this case, 2,4,4-trimethyl-2-pentene yields a mixture of $(CH_{3})_{2}C=O$ and $(CH_{3})_{3}CHO$

The reaction process is illustrated below.

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25 days ago

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The production of NOx gases is an unwanted side reaction of the main engine combustion process that turns octane, C8H18, into CO

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11 days ago

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1 month ago

A metallic object holds a charge of −4.8 × 10−6 C. What total number of electrons does this represent? (e = 1.6 × 10−19 C is the

Anarel [2600]

Answer:

$n=3.0\times 10^{13}$

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Charge of one electron = $-1.6\times 10^{-19}\ C$

The formula for calculating charge is:

$Charge=n\times q_e$

Given that: Charge = $-4.8\times 10^{-6}\ C$

$-4.8\times 10^{-6}=n\times (-1.6\times 10^{-19})$

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1 month ago

A typical deposit of cholesterol,C27H460,in an artery has a mass of 3.90mg.how many molecules of cholesterol are present in this

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The quantity is 6.074 X 10¹⁸ molecules. To calculate the molecular weight (MM) of the compound C₂₇H₄₆O, we use the formula: 27*(MM of C) + 46*(MM of H) + (MM of O). This leads to: 27*(12.0107) + 46* (1.00784) + (15.999) = 324.2889 + 46.36064 + 15.999 = 386.64854 g. The molar mass of any compound indicates the number of molecules found in one mole, which is 6.022 X 10²³ (Avogadro's number). So, if 386.64854 g of C₂₇H₄₆O consists of 6.022 X 10²³ cholesterol molecules, we can determine how many molecules are found in a deposit of 3.9mg or 0.0039g of C₂₇H₄₆O by using the unitary method. Number of molecules = 6.074 X 10¹⁸ molecules.

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11 days ago