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2 months ago

How many atoms of Mg are present in 97.22 grams of Mg?

Chemistry

1 answer:

VMariaS [2.9K]2 months ago

7 0

Answer: The correct choice is (b).

Explanation:

We have the mass of Magnesium at 97.22 g, and the molar mass of Magnesium is 24.305 g/mol.

Therefore, the calculation for the number of moles is as follows.

Number of moles = $\frac{mass given in grams}{Molar mass}$

= $\frac{97.22 g}{24.305 g/mol}$

= 4 mol

Additionally, it is known that one mole contains $6.023 \times 10^{23}$ atoms/mol. Thus, we calculate the total number of atoms in 4 moles as follows.

$4 mol \times 6.023 \times 10^{23} atoms/mol$

= $24.08 \times 10^{23}$ atoms

or, = $2.408 \times 10^{23}$ atoms

Hence, we conclude that in 97.22 grams of Magnesium, there are $2.408 \times 10^{23}$ atoms.

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A common characteristic of alkali metals is their reactive behavior with water, resulting in the formation of the respective hydroxide and hydrogen gas.

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